All categories

3 years ago

Find the measure of t given that p

Mathematics

1 answer:

pychu [463]3 years ago

5 0

Answer:

m∠t = 143°

m∠x = m∠t

i'm just ordinary human, CMIIW

You might be interested in

Please help . Gets brainlest answer!!

AysviL [449]

3. -x²+-4x+-8

To solve:

−4x−5+−1(x²+3)

−4x+−5+−1x²+(−1)(3)

−4x+−5+−x²+−3

Combine like terms.

−4x+−5+−x²+−3

(−x²)+(−4x)+(−5+−3)

It is not in standard form since this answer does NOT have x=, y=, #=. It only has the numbers. So, this is NOT in standard form.

6 0

3 years ago

Given the figure below solve for X

enot [183]

Answer:

x = 37

Step-by-step explanation:

7 0

2 years ago

The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta

earnstyle [38]

Answer:

The probability that none of the meals will exceed the cost covered by your company is 0.2637.

Step-by-step explanation:

A hyper-geometric distribution is used to define the probability distribution of k success in n samples drawn from a population of size N which include K success. Every draw is either a success of failure.

The random variable X = number of meals that will exceed the cost covered by the company.

The random variable X follows a hyper-geometric distribution.

The information provided is:

N = 15

K = 3

n = 5

k = 0

The probability mass function of a hyper-geometric distribution is:

$P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}$

Compute the probability that none of the meals will exceed the cost covered by your company as follows:

$P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637$

Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.

3 0

3 years ago

How many seconds it takes for the ball to hit the ground

Dovator [93]

T = 5.123494 seconds

3 0

3 years ago

Use the t-distribution and the sample results to complete the test of the hypotheses. Use a significance level. Assume the resul

Ksenya-84 [330]

Answer:

Test statistic = 1.3471

P-value = 0.1993

Accept the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 4

Sample mean, $\bar{x}$ = 4.8

Sample size, n = 15

Alpha, α = 0.05

Sample standard deviation, s = 2.3

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 4\\H_A: \mu \neq 4$

We use two-tailed t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{4.8 - 4}{\frac{2.3}{\sqrt{15}} } = 1.3471$

Now, we calculate the p-value.

P-value = 0.1993

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept it.

3 0

3 years ago