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ipn [44]
3 years ago
11

There is 5/6 of and apple left from dinner.How much of the whole pie will be left after he eats tomorrow?

Mathematics
1 answer:
ZanzabumX [31]3 years ago
8 0

Answer:

Step-by-step explanation:

If Vic eats 1/6 of 5/6, then he ate (1/6) * (5/6) = 5/36 of the original pie

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Pacturing Polynomials! GCH
grin007 [14]
Gross pay per days is 5h+8 dollars
Explanation:

we are given
total gross pay =35h+56 dollars
total number of days =7
we know that
gross pay per day = ( total gross pay)/(total number of days)
we can plug values
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7 0
3 years ago
What's the input lol *photo attatched*​
marishachu [46]
-20+1= -19
-19/2= -9.5

Check:
-9.5x2= -19
-19-1= -20
3 0
2 years ago
Which shows all the values of x that make the rational expression undefined? x = 6 x = 7 x = –6 or x = 6 x = –7 or x = 7
n200080 [17]
<h2>Explanation:</h2>

The rational expression is given by:

E=\frac{2x^2-72}{5x^2-245} \\ \\ Factor \ out: \\ \\  E=\frac{2(x^2-36)}{5(x^2-49)} \\ \\ E=\frac{2(x-6)(x+36)}{5(x-7)(x+7)} : \ \ \ \ a^2-b^2=(a-b)(a+b)

The denominator can't be zero, therefore:

(x-7)(x+7)\neq 0 \\ \\ \\ Thus: \\ \\ \boxed{x\neq 7 \ and x \neq -7}

Finally,<em> the values of x that make the rational expression undefined are </em>

<em></em>

<em>x = 7 and x = -7</em>

4 0
3 years ago
What is the effect if two parallel lines are rotated 90° clockwise?
Fed [463]

Answer:

the first one

Step-by-step explanation:

if you have a ladder with no steps and it is leaning on a wall it will be facing up if you carry that ladder sideways it will still be parrallel to the opposite poles

if this confuss you I will answer again

7 0
3 years ago
Please Help ASAP!!
Brilliant_brown [7]

Answer:

The probably genotype of individual #4 if 'Aa' and individual #6 is 'aa'.

Step-by-step explanation:

In a non sex-linked, dominant trait where both parents carry and show the trait and produce children that both have and don't have the trait, they would each have a genotype of 'Aa' which would produce a likelihood of 75% of children that carry the dominant traint and 25% that don't.  Since the child of #1 and #2, #5, does not exhibit the trait, nor does the significant other (#6), then they both must have the 'aa' genotype.  However, since #4 displays the dominant trait received from the parents, it is more likely they would have the 'Aa' genotype as by the punnet square of 'Aa' x 'Aa', 50% of their children would have the 'Aa' phenotype.  

4 0
3 years ago
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