The equation of the tangent line at x=1 can be written in point-slope form as
... L(x) = f'(1)(x -1) +f(1)
The derivative is ...
... f'(x) = 4x^3 +4x
so the slope of the tangent line is f'(1) = 4+4 = 8.
The value of the function at x=1 is
... f(1) = 1^4 +2·1^2 = 3
So, your linearization is ...
... L(x) = 8(x -1) +3
or
... L(x) = 8x -5
Answer:
#1-List all outcomes for choosing the digit. *
0)
O
A: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10
B: 0, 1, 2, 3, 4, 5, 6, 7, 8, 9
C: 1, 2, 3, 4, 5, 6, 7, 8, 9
OD: a number
Both B and C
Step-by-step explanation:
Answer: 321.4167 or about 322 boxes