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Aleonysh [2.5K]
3 years ago
5

SOLVE THE2x-3 -16i) 3x - [3 (1+x)-2x] = 3​

Mathematics
1 answer:
katovenus [111]3 years ago
5 0

Answer:

X= 1/2 or 0.5

Step-by-step explanation:

2x^-3 = 16

x^-3 = 8

1/x^3 = 8

1 = 8x^3

1/8 = x^3

Cube root of 8 is 2

1/2 = x

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We have that the total students there are 500. The 12-graders there are 200. Probability is defined as the ratio of positive outcomes of an event, over all the possible outcomes. Suppose we pick student randomly. Then, there are 200 positive outcomes (positive outcome: we pick a student in 12th grade) and there are totally 500 outcomes (we can pick 500 students in total from Riverside High School). This ratio gives: P= \frac{200}{500} =0.4. The requested probability is 0.40
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Can someone help me with these two questions?
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Answer:

17) A(-1,1) B(-1,4) C(5,1)

18) (From origin moving rightwards)

     A(0,0) B(a, 0) C(a,a) D(0,a)

Step-by-step explanation:

17) You just count the steps, how many steps left, right, up, or down

18) The first point is at the origin, so 0,0

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5 0
3 years ago
2x+4=18 <br> what does 'x' equal?
astra-53 [7]

Answer:

7

Step-by-step explanation:

18-4

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hoped this helped

5 0
3 years ago
Pyramid A has a triangular base where each side measures 4 units and a volume of 36 cubic units. Pyramid B has the same height,
omeli [17]

Answer:

The volume of pyramid B is 81 cubic units

Step-by-step explanation:

Given

<u>Pyramid A</u>

s = 4 -- base sides

V = 36 -- Volume

<u>Pyramid B</u>

s = 6 --- base sides

Required

Determine the volume of pyramid B <em>[Missing from the question]</em>

From the question, we understand that both pyramids are equilateral triangular pyramids.

The volume is calculated as:

V = \frac{1}{3} * B * h

Where B represents the area of the base equilateral triangle, and it is calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where s represents the side lengths

First, we calculate the height of pyramid A

For Pyramid A, the base area is:

B = \frac{1}{2} * s^2 * sin(60)

B = \frac{1}{2} * 4^2 * \frac{\sqrt 3}{2}

B = \frac{1}{2} * 16 * \frac{\sqrt 3}{2}

B = 4\sqrt 3

The height is calculated from:

V = \frac{1}{3} * B * h

This gives:

36 = \frac{1}{3} * 4\sqrt 3 * h

Make h the subject

h = \frac{3 * 36}{4\sqrt 3}

h = \frac{3 * 9}{\sqrt 3}

h = \frac{27}{\sqrt 3}

To calculate the volume of pyramid B, we make use of:

V = \frac{1}{3} * B * h

Since the heights of both pyramids are the same, we can make use of:

h = \frac{27}{\sqrt 3}

The base area B, is then calculated as:

B = \frac{1}{2} * s^2 * sin(60)

Where

s = 6

So:

B = \frac{1}{2} * 6^2 * sin(60)

B = \frac{1}{2} * 36 * \frac{\sqrt 3}{2}

B = 9\sqrt 3

So:

V = \frac{1}{3} * B * h

Where

B = 9\sqrt 3 and h = \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9\sqrt 3 * \frac{27}{\sqrt 3}

V = \frac{1}{3} * 9 * 27

V = 81

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