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Bingel [31]
3 years ago
12

What is the approximate value of ? Round your answer to the nearest hundredth. 1.99 2.38 2.50 4.98

Mathematics
2 answers:
andrew11 [14]3 years ago
7 0

Answer:

Step-by-step explanation:

Missing info !    Try to get it posted so we can help......

fiasKO [112]3 years ago
7 0

Answer:D

Step-by-step explanation:

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25 POINTS SOMEONE HELP ME OUT WITH THIS PLEASEEEE BRAINLIEST ANSWER
zloy xaker [14]
1. y=7x-1

2. y=3x+b
   <u> </u><u>Sub (1, -5) into equation to find '</u><em><u>b'</u></em><u />
   -5=3(1)+b
   -8=b

   y=3x-8 

3. x=-7

4. y=4
3 0
3 years ago
If A = {1, 3, 5, 7, 9} and B = {2, 3, 5, 7}, what is A U B?
Phoenix [80]

Answer:

Answer is A U B = {3,5,7}

3 0
3 years ago
EASY POINTS Find the domain of the graphed function.
Vladimir [108]

Using it's concept, it is found that the domain of the graphed function is given as follows:

D. -4 \leq x \leq 2

<h3>What is the domain of a function?</h3>

It is the set that contains all possible input values for the function. In a graph, it is given by the values of x.

In this graph, x assumes values between -4 and 2, inclusive due to the closed circle, hence the domain is given by:

D. -4 \leq x \leq 2

More can be learned about the domain of a function at brainly.com/question/10891721

#SPJ1

4 0
2 years ago
1. Find the value of
spin [16.1K]

9514 1404 393

Answer:

  1. -√5
  2. 3/5
  3. -4/5

Step-by-step explanation:

The relevant relations are ...

  sec = ±√(tan² +1)

  cos = 1/sec

  csc = 1/sin = ±1/√(1 -cos²)

Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.

__

1. sec(θ) = -√((-2)² +1) = -√5

2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5

3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5

8 0
3 years ago
For a school fundraiser students are selling snack bags and candy bars to raise money on Wednesday the students or 23 snack bags
meriva

Answer:

$1.75

Step-by-step explanation:

The selling for each candy bar may be determined by  a set of linear equations. This pair of linear equations may be solved simultaneously by using the elimination method. This will involve ensuring that the coefficient of one of the unknown variables is the same in both equations.

It may be solved by substitution in that one of the variable is made the subject of the equation and the result is substituted into the second equation .

Let the cost of a snack bag be s and that of a candy bar be c, then if on Wednesday the students or 23 snack bags and 36 candy bars that raised $114.75 on Thursday the seventh so 37 snack bags and 36 candy bars that raised $146.25

23s + 36c = 114.75

37s + 36c = 146.25

14s = 31.5

s = $2.25

23(2.25) + 36c = 114.75

36c = 114.75 - 51.75

36c = 63

c = 63/36

= $1.75

3 0
3 years ago
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