Answer:
Step-by-step explanation:
The question is incomplete. Here is the complete question;
A kid traveled a distance of 9 km by bike, and then walked a distance of x km.
a.Find the total distance traveled in terms of x
b. If the total distance was less than 30 km, form an inequality in x, and
then solve it!
a) Total distance = distance travelled by bike + distance walked
Total distance = 9km + xkm
Total distance = (9+x)km
b) If the total distance was less than 30 km, the inequality representing this is;
9+x < 30
Subtract 9 from both sides;
9+x-9 < 30-9
x < 21
hence the solution to the inequality is x< 21
Answer:
-3/4
Step-by-step explanation:
Move the 3x over to the side with the 3 so it will become a -3x now you have 4y=-3x+3 now you have to remove the 4 from the y so now you have y=-3/4x+3/4 so you slope will be -3/4
Answer:
Mean: 49
Mode: none, since all the numbers only appear once
Median: 48
Range: 69
Step-by-step explanation:
53+64+19+25+88+48+46 = 343
343/7= 49 (mean)
19, 25, 26, 48, 53, 64, 88 (middle number is 48, so the median is 48)
Range= largest number-smallest number
88-19= 69 (range)
The +7 means we shift f up 7 units.
The -2 means what was f(0) before is g(2) so we're shifting f 2 units to the right to get g.
Answer: Incorrect, Gia switched left and right
Answer:
Arc BC is 64°
Step-by-step explanation:
The parameters given are;
∠CAB = 32°
We note that the measure of arc BC = ∠CDB
∠DCA = ∠CAB = 32° (Base angles of an isosceles triangle)
∠ACB = 90° (Angle subtended at the center = Twice angle subtended at the circumference)
∠ACB = ∠DCB + ∠DCA
∴ ∠DCB = ∠ACB - ∠DCA = 90° - 32° = 58°
∠DBC = ∠DCB = 58° (Base angles of an isosceles triangle)
∴ ∠CDB + ∠DBC + ∠DCB = 180° (Sum of interior angles of a triangle)
∠CDB = 180° - (∠DBC + ∠DCB) = 180° - (58° + 58°) = 64°
∠CDB = Arc BC = 64°