If 4 people are selected from a group of 6 married couples, what is the probability that none of them would be married to each o
ther?
1 answer:
Answer:
16/33
Step-by-step explanation:
12C4(total possible outcomes)=495
Since there are 6 married couples there must be 6*[2C2×10C2]=270
must subtracted 15 since when there are 2 couples in a group would have doubled 270-15=255
the no of groupings with no married couples 495-255 =240
probability=no of favourable outcomes /no of possible outcome
probability=240/495= 16/33
You might be interested in
Answer:
c and d I think but not quite sure
Answer:
L to K
K to J
Step-by-step explanation:
the length between L and K is shorter when compared the side K to J
hope it helps :)
Answer:
Step-by-step explanation:
<u>Seven less than the product of a number n and 1/6 is no more than 94, translating:</u>
<u>Solving for n:</u>
- n/6 ≤ 94 + 7
- n/6 ≤ 101
- n ≤ 101*6
- n ≤ 606
Answer:
5 rooms
Step-by-step explanation:
7.5 divided by 1.5 is equal to 5
Answer:
-2
Step-by-step explanation:
slope = (y1-y2)/(x1-x2)
= (3-1)/(0-1)
= 2/-1
= -2
