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3 years ago

What's 482 rounded to the nearest 10

Mathematics

1 answer:

Fantom [35]3 years ago

8 0

The answer to this would be 480. ((:

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What fraction is larger 7/8 or 14/16

Bas_tet [7]

7*2=14 8*2=16 which is 14/16 so they are the same

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3 years ago

If the total sticker price on a new car is $42,055 and you have to pay 7% sales tax, how much will you have to pay for the vehic

tresset_1 [31]

Answer:

$44,998.85

Step-by-step explanation:

Price of the car = $42,055

Tax = 7%

Total cost = Price of the car + amount of tax

= 42,055 + 7% of 42,055

= 42,055 + 7/100 * 42,055

= 42,055 + 0.07 * 42,055

= 42,055 + 2,943.85

= 44,998.85

Total cost = $44,998.85

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3 years ago

Does 36x+24=12(x+2+2x) , have no solution, one solution, many solutions?

Reika [66]

Answer:

No solution

Step-by-step explanation:

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3 years ago

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does anyone have Skype or Outlook and do you want to join a Skype if you have Skype if you have Outlook email me

MaRussiya [10]

Answer:

not today

Step-by-step explanation:

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3 years ago

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Use the properties of limits to help decide whether the limit exists. If the limit exists, find its value. ModifyingBelow lim W

Sergeu [11.5K]

Answer:

The value of given limit problem is 0.

Step-by-step explanation:

The given limit problem is

$lim_{x\rightarrow \infty}\dfrac{6x^3+5x-7}{6x^4-4x^3-9}$

We need to find the value of given limit problem.

Divide the numerator and denominator by the leading term of the denominator, i.e., $x^4$

$lim_{x\rightarrow \infty}\dfrac{\frac{6x^3+5x-7}{x^4}}{\frac{6x^4-4x^3-9}{x^4}}$

$lim_{x\rightarrow \infty}\dfrac{\frac{6}{x}+\frac{5}{x^3}-\frac{7}{x^4}}{6-\frac{4}{x}-\frac{9}{x^4}}$

Apply limit.

$\dfrac{\frac{6}{ \infty}+\frac{5}{ \infty}-\frac{7}{ \infty}}{6-\frac{4}{ \infty}-\frac{9}{ \infty}}$

We know that $\frac{1}{\infty}=0$ .

$\dfrac{0+0-0}{6-0-0}$

$\dfrac{0}{6}$

$0$

Hence, the value of given limit is 0.

8 0

3 years ago