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Novay_Z [31]
4 years ago
10

Item 10

Mathematics
1 answer:
vekshin14 years ago
7 0

Answer:

1.75

Step-by-step explanation:

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I need help ASAP pleaseee
Tanya [424]

Answer:Price of laptop A = $1220

Step-by-step explanation:

Sum of the price: A + B = 2185

Sum of the price: A + C = 2571

B : C = 5 : 7

B = 5/7 × C

So, replace the B:

A + 5/7 C = 2185

A + C = 2571

Eliminate by subtracting the first from the second: 2/7 C = 386

C = 1351

So, A = 2571 - 1351 = 1220

3 0
3 years ago
Integrate the following problem:
vazorg [7]

Answer:

\displaystyle \frac{2 \cdot sin2x-cos2x}{5e^x} + C

Step-by-step explanation:

The integration by parts formula is: \displaystyle \int udv = uv - \int vdu

Let's find u, du, dv, and v for \displaystyle \int e^-^x \cdot cos2x \ dx .

  • u=e^-^x
  • du=-e^-^x dx
  • dv=cos2x \ dx
  • v= \frac{sin2x}{2}

Plug these values into the IBP formula:

  • \displaystyle \int e^-^x \cdot cos2x \ dx = e^-^x \cdot \frac{sin2x}{2} - \int \frac{sin2x}{2} \cdot -e^-^x dx
  • \displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \int \frac{sin2x}{2} \cdot -e^-^x dx

Now let's evaluate the integral \displaystyle \int \frac{sin2x}{2} \cdot -e^-^x dx.

Let's find u, du, dv, and v for this integral:

  • u=-e^-^x
  • du=e^-^x dx
  • dv=\frac{sin2x}{2} dx
  • v=\frac{-cos2x}{4}  

Plug these values into the IBP formula:

  • \displaystyle \int -e^-^x \cdot \frac{sin2x}{x}dx = -e^-^x \cdot \frac{-cos2x}{4} - \int \frac{-cos2x}{4}\cdot e^-^x dx

Factor 1/4 out of the integral and we are left with the exact same integral from the question.

  • \displaystyle \int -e^-^x \cdot \frac{sin2x}{x}dx = -e^-^x \cdot \frac{-cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx

Let's substitute this back into the first IBP equation.

  • \displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \Big [ -e^-^x \cdot \frac{-cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx \Big ]  

Simplify inside the brackets.

  • \displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} - \Big [ \frac{e^-^x \cdot cos2x}{4} + \frac{1}{4} \int cos2x \cdot e^-^x dx \Big ]

Distribute the negative sign into the parentheses.

  • \displaystyle \int e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} -  \frac{e^-^x \cdot cos2x}{4} - \frac{1}{4} \int cos2x \cdot e^-^x dx

Add the like term to the left side.

  • \displaystyle \int e^-^x \cdot cos2x \ dx  + \frac{1}{4} \int cos2x \cdot e^-^x dx= \frac{e^-^x sin2x}{2} -  \frac{e^-^x \cdot cos2x}{4}  
  • \displaystyle \frac{5}{4} \int   e^-^x \cdot cos2x \ dx = \frac{e^-^x sin2x}{2} -  \frac{e^-^x \cdot cos2x}{4}  

Make the fractions have common denominators.

  • \displaystyle \frac{5}{4} \int   e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x}{4} -  \frac{e^-^x \cdot cos2x}{4}

Simplify this equation.

  • \displaystyle \frac{5}{4} \int   e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{4}

Multiply the right side by the reciprocal of 5/4.

  • \displaystyle \int   e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{4} \cdot \frac{4}{5}

The 4's cancel out and we are left with:

  • \displaystyle \int   e^-^x \cdot cos2x \ dx = \frac{2e^-^x sin2x - e^-^x cos2x}{5}

Factor e^-^x out of the numerator.

  • \displaystyle \int   e^-^x \cdot cos2x \ dx = \frac{e^-^x(2 \cdot sin2x-cos2x)}{5}

Simplify this by using exponential properties.

  • \displaystyle \int   e^-^x \cdot cos2x \ dx = \frac{2 \cdot sin2x-cos2x}{5e^x}

The final answer is \displaystyle \int   e^-^x \cdot cos2x \ dx = \frac{2 \cdot sin2x-cos2x}{5e^x} + C.

7 0
3 years ago
Read 2 more answers
Ron and Harry both parked their cars at a parking lot. Ron parked his car for 8 hours at $3 per hour and Harry parked his car fo
SpyIntel [72]
Alright, so Ron parked his car for 8 hours at $3 per hour.

Harry parked his car for 7 hours at $3 per hour.

So, per day Ron is spending (8 * 3) = $24 a day
and Harry is spending ( 7 * 3 ) = $21 a day

So now solve for 5 days. 24 * 5 = $120 21 * 5 = $105

Add both together
$120
+
$105

=
Your Answer:
$225 altogether.


4 0
4 years ago
Read 2 more answers
ABCD is a rectangle. Find the length of segment AC
Oksana_A [137]

Answer:

52

Step-by-step explanation:

First, find x. As BE and DE will have the same measurements, you can set your formula up as

5x+11=3x+17

5x=3x+17-11

5x-2x=6

2x=6

x=6/2

x=3

CE and AE will also have the same value, now substitute 3 in place of x to get the value of segment BE

5x+11

5*3+11 = 26

This also means that CE = 26 and AE = 26

AC = CE + AE

AC = 52

4 0
3 years ago
Do these side lengths make a triangle?<br> 8 8 4
chubhunter [2.5K]

Answer:

Yes, isosceles triangle

Step-by-step explanation:

Side lengths of 8, 8, and 4 will make an isosceles triangle.

It would look something like this:

7 0
3 years ago
Read 2 more answers
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