How many zeros does the function f(x)=15x^17+41x^12+13x^13-10 have?

Mathematics

1 answer:

Butoxors [25]3 years ago

5 0

Answer:

Step-by-step explanation:

According to the graph below there are just 3 real zeros. If you count everything, there would be 17. I have chosen the real ones. But there are 14 others that all involve complex numbers. I don't know how you would find them.

Summary

There are 17 roots in total. 3 are real.

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At Manny's taco shop, you can get an order of chips and two tacos for $9.25. The cost for two orders of chips and five tacos is

Sedbober [7]

<h3>Define your variables:</h3>

At Manny's taco shop, you can get an order of chips and two tacos for $9.25. The cost for two orders of chips and five tacos is $21.75.

<h2>x = Chips</h2><h2>y = Tacos</h2>

<h3>Write your system of Equations:</h3>

<u>You can get </u><u>an </u><u>order of </u><u>chips </u><u>and </u><u>two tacos </u><u>for </u><u>$9.25</u><u>. </u>

1 Chips + 2 Tacos = 9.25

<u>The cost for </u><u>two </u><u>orders of </u><u>chips </u><u>and </u><u>five tacos </u><u>is </u><u>$21.75</u><u>.</u>

2 Chips + 5 Tacos = 21.75

<h2>2x + 5y = 21.75</h2><h2 /><h3>Solve The System:</h3>

First equate the coefficient - in this case x:

(x + 2y = 9.25) * 2 = 2x + 4y = 18.50

2x + 4y = 18.50

2x + 5y = 21.75

Minus the equations from each other to remove the coefficient you equated: