For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
Answer:
Pretty sure it's (4, -5)
Step-by-step explanation:
If not, shoot me I guess.
Answer:
27
Step-by-step explanation:
So first we need to plug in 5 as the variable a and -7 as the variable b
4(5)-(-7)
Next we multiply the 4 and the 5 together to get 20
4(5) = 20 or 4 x 5 = 20
20-(-7)
Now we subtract negative 7 from 20
20-(-7) = 27
This can also be written as 20 plus 7 as a mathematical rule states: two negatives make a positive. So:
20-(-7) = 20 + 7
Both of these are equivalent in every sense of the word and give us our final answer of 27
Answer:
(x-4)^2 + (y-3)^2 =8
Step-by-step explanation:
The midpoint of the diameter is (6+2)/2= 4, (5+1)/2 = 3
(4,3)
The radius is the distance from the midpoint to an endpoint
This is 2sqrt(8)
So the equation is
(x-4)^2 + (y-3)^2 =8
Answer:
- 3a³ + 5a² - 3a + 7
Step-by-step explanation:
Given
(a³ - 2a + 5) - (4a³ - 5a² + a - 2)
Distribute both parenthesis noting the second is distributed by - 1
= a³ - 2a + 5 - 4a³ + 5a² - a + 2 ← collect like terms
= (a³ - 4a³ ) + 5a² + (- 2a - a) + (5 + 2)
= - 3a³ + 5a² - 3a + 7
