
Therefore, there are

millimeters in seven meters.
Answer:
√
96
log
(100
)
3
^5
/ 3
Step-by-step explanation:
Answer:
B) always less than either of the original fractions
Step-by-step explanation:
We can easily Answer this by taking some values.
The question states that the two fractions, each have values between 0 and 1.
Let us say one of the fraction is 1/2 and the other fraction is 1/3 .
The product of the two fractions is 1/2 x 1/3 = 1/6 .
is lesser than both 1/2 and 1/3 .
So, the correct answer is that the product is always less than either of the original fractions.
The plot that organizes the data into 4 groups of equal sizes is box and whisker plot.
The image below shows a box and whisker plot. Following are the elements of box and whisker plot:
Minimum = This is the smallest value of the data set
Q1 = First (Lower) Quartile of the data set. 25% of the data values lie below this point
Q2 = Second Quartile or Median. This is the central value so 50% of the data values lie below this point
Q3 = Third (Upper) Quartile of the data set. 75% of the data values lie below this point.
Maximum = This is the maximum value of the data set.
Based on box and whisker plot we can compare two or more sets of data by comparing the spread of the data. We can also directly observe from the box and whisker plot if the data is uniform, normal or skewed. Using box and whisker plot we can also visualize any outliers that may be in the data.
Answer:
<h2>16kg</h2>
Step-by-step explanation:
This problem is borers on elasticity of materials.
according to Hooke's law,<em> "provided the elastic limit of an elastic material is not exceeded the the extension e is directly proportional to the applied force."</em>

where F is the applied force in N
k is the spring constant N/m
e is the extension in meters
Given data
mass m= 24kg
extensnion=15cm in meters=
= 
we can solve for the spring constant k
we also know that the force F = mg
assuming 
therefore

We can use this value of k to solve for the mass that will cause an extension of 
