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nika2105 [10]
2 years ago
9

In parallelogram GHJK if m∡GHJ=140˚ find m ∡KGH.

Mathematics
2 answers:
Lera25 [3.4K]2 years ago
6 0

Answer: m∠x = 40°

Step-by-step explanation:

This works the exact same way as the other one

Being adjacent angles in a parallelogram, the two angles would be supplementary (add up to 180°).

140° + x° = 180°

x = 40°

katovenus [111]2 years ago
3 0
67 degrees because X equal 7 and nkdh
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How would you solve this? help.
Eddi Din [679]

Answer:

<em>Center: (3,3)</em>

<em>Radius: </em>2\sqrt{5}<em />

Step-by-step explanation:

<u>Midpoint and Distance Between two Points</u>

Given two points A(x1,y1) and B(x2,y2), the midpoint M(xm,ym) between A and B has the following coordinates:

\displaystyle x_m=\frac{x_1+x_2}{2}

\displaystyle y_m=\frac{y_1+y_2}{2}

The distance between both points is given by:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Point (5,7) is the center of circle A, and point (1,-1) is the center of the circle B. Given both points belong to circle C, the center of C must be the midpoint from A to B:

\displaystyle x_m=\frac{5+1}{2}=\frac{6}{2}=3

\displaystyle y_m=\frac{7-1}{2}=\frac{6}{2}=3

Center of circle C: (3,3)

The radius of C is half the distance between A and B:

d=\sqrt{(1-5)^2+(-1-7)^2}

d=\sqrt{16+64}=\sqrt{80}=\sqrt{16*5}=4\sqrt{5}

The radius of C is d/2:

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Radius: 2\sqrt{5}

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solution is in the attachment

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