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3 years ago

Please help ASAP (30 POINTS)

Mathematics

1 answer:

Ede4ka [16]3 years ago

7 0

Answer:

Low

Step-by-step explanation:

Low because it only overlaps twice.

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Square root of x^2-4 plus x^2/x^2+1

Akimi4 [234]

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3 years ago

The graph shows that is translated horizontally and vertically to create the function .

Sholpan [36]

Answer: H=2 i just took the test

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Toniac 123 can you please help me with these questions. They are part of of the question you answered. There is another question

uranmaximum [27]

5/12+5/12=10/12
10/12+10/12=20/12 wich =1.666666666666667theres ur answer to one.
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8 0

4 years ago

20/12=15/x find x plz help

Ganezh [65]

Answer:

$x = 9$

Step-by-step explanation:

To find x, we first have to solve the equation given in the question:

$\frac{20}{12} = \frac{15}{x}$

$20x = 15 \cdot 12$

$x = \frac{180}{20}$

$x = 9$

Therefore, x = 9.

Hope this helped!

3 0

3 years ago

Read 2 more answers

Several terms of a sequence {an}n=1 infinity are given. A. Find the next two terms of the sequence. B. Find a recurrence relatio

s344n2d4d5 [400]

Answer:

A) $\frac{1}{1024},\frac{1}{4096}$

B) $\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) $\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

Step-by-step explanation:

1) Incomplete question. So completing the several terms: $\left \{a_{n}\right \}_{n=1}^{\infty}=\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},... \right \}$

We can realize this a Geometric sequence, with the ratio equal to:

$q=\frac{1}{4}$

A) To find the next two terms of this sequence, simply follow multiplying the 5th term by the ratio (q):

$\frac{1}{256}*\mathbf{\frac{1}{4}}=\frac{1}{1024}\\\\\frac{1}{1024}*\mathbf{\frac{1}{4}}=\frac{1}{4096}\\\\\left \{ 1,\frac{1}{4},\frac{1}{16},\frac{1}{64},\frac{1}{256},\mathbf{\frac{1}{1024},\frac{1}{4096}}\right \}$

B) To find a recurrence a relation, is to write it a function based on the last value. So that, the function relates to the last value.

$\left\{\begin{matrix}a(1)=1 & \\ a(n)=a(n-1)*\frac{1}{4} &\:for\:n=1,2,3,4,... \end{matrix}\right.$

C) The explicit formula, is one valid for any value since we have the first one to find any term of the Geometric Sequence, therefore:

$\\a_{n}=nq^{n-1} \:for\:n=1,2,3,4,...$

6 0

3 years ago