Answer:
hope this helps. I am also a learner like you. Please cross check my explanation.
Explanation:
#include
#include
using namespace std;
int main()
{
int a[ ] = {0, 0, 0}; //array declared initializing a0=0, a1=0, a3=0
int* p = &a[1]; //pointer p is initialized it will be holding the address of a1 which means when p will be called it will point to whatever is present at the address a1, right now it hold 0.
int* q = &a[0]; //pointer q is initialized it will be holding the address of a0 which means when q will be called it will point to whatever is present at the address a0, right now it hold 0.
q=p; // now q is also pointing towards what p is pointing both holds the same address that is &a[1]
*q=1
; //&a[0] gets overwritten and now pointer q has integer 1......i am not sure abut this one
p = a; //p is now holding address of complete array a
*p=1; // a gets overwritten and now pointer q has integer 1......i am not sure abut this one
int*& r = p; //not sure
int** s = &q; s is a double pointer means it has more capacity of storage than single pointer and is now holding address of q
r = *s + 1; //not sure
s= &r; //explained above
**s = 1; //explained above
return 0;
}
Answer:
The correct option is option 3 which is The code segment works as intended but only when the sum of the three lengths is an integer or the decimal part of the sum of the three lengths is greater than or equal to 0.5.
Explanation:
As the variable minLength is defined as an integer thus the value is being truncated although the value of 0.5 is being added however if the decimal portion of the length is less than 0.5, the portion is truncated.
Answer:
B) computeValue(10);
Explanation:
Given
Header: void computeValue(int value)
Required
Determine the valid call
To call a function from another function or from the main, the following syntax has to be used.
<em>function-name(parameter-1, parameter-2, parameter-3,.....,parameter-n);</em>
<em />
In the function header given:, the following can be observed:
- The function name is computeValue
- It has only one parameter and it is of type integer
So, to call the function; we make use of computeValue(10);
Where 10 represents the value of the parameter (i.e. argument)
