Answer:
Trap is a software interrupt that occurs when there is a system call, while hardware interrupt occurs when a hardware component needs urgent attention.
Explanation:
Interrupt is an input signal that disrupt the activities of a computer system, giving immediate attention to a hardware or software request.
In trap interrupt, the system activities are stop for a routine kernel mode operation, since it has a higher priority than the user mode. At the end of the interrupt, it switches control to the user mode.
The hardware interrupt is a signal from hardware devices like the input/output devices, storage and even peripheral devices that draws an immediate attention of the processor, stopping and saving other activities and executing the event with an interrupt handler.
terms = ["Bandwidth", "Hierarchy", "IPv6", "Software", "Firewall", "Cybersecurity", "Lists", "Program", "Logic",
"Reliability"]
def swap(arr, in1, in2):
w = arr[in1]
arr[in1] = arr[in2]
arr[in2] = w
print(terms)
swap(terms, 5, 1)
swap(terms, 2, 4)
swap(terms, 3, 5)
swap(terms, 5, 6)
swap(terms, 6, 8)
swap(terms, 8, 9)
print(terms)
This is how I interpreted the question. If I need to make any changes, I'll do my best. Hope this helps though.
Answer:
#include <iostream>
using namespace std;
void PrintPopcornTime (int bagOunces){
if (bagOunces < 2){
cout << "Too small"<<endl;
}
else if (bagOunces > 10){
cout << "Too large"<<endl;
}
else{
cout << bagOunces*6 <<" seconds"<<endl;
}
}
int main(){
PrintPopcornTime(7);
return 0;
}
Explanation:
Create a function called PrintPopcornTime that takes one parameter, bagOunces
Check the bagOunces using if-else structure. If it is smaller than 2, print "Too small". If it is greater than 10, print "Too large". Otherwise, calculate and print 6*bagOunces followed by " seconds".
Call the function in the main function with parameter 7. Since 7 is not smaller than 2 or not greater than 10, "42 seconds" will be printed.
