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Goryan [66]
3 years ago
7

Translate the new algebraic expression you created in Question 1 to a verbal expression.

Mathematics
1 answer:
svetoff [14.1K]3 years ago
6 0

Answer:

What are you asking?

Step-by-step explanation:

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-3 is an integer and rational number
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A triangle cannot have more than _________ right angle.​
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Y hzuzjz is a complete* of the following elements has the largest atomic size in the world is the difference between

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Write the equation of the line that has a slope of 3 and passes through (5, 11)
Marina CMI [18]

Answer:

3x-4

Step-by-step explanation:

y=ax+b general type of the line

a is the slope

y=3x+b

put 5 instead of the x and put 11 instead of the y

11=15+b

b=(-4)

Equation is 3x-4

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2 years ago
How does 10 to the 2nd power -8 +4 x 3 =288?
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Answer:

Step-by-step explanation:

((10²-8)+4)×3=288

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7 0
3 years ago
PLEASE HELP 10pts
Veronika [31]

Answer:

Hence the function which has the smallest minimum is: h(x)

Step-by-step explanation:

We are given function f(x) as:

  • f(x) = −4 sin(x − 0.5) + 11

We know that the minimum value attained by the sine function is -1 and the maximum value attained by sine function is 1.

so the function f(x) receives the minimum value when sine function attains the maximum value since the term of sine function is subtracted.

Hence, the minimum value of f(x) is: 11-4=7 ( when sine function is equal to 1)

  • Also we are given a table of values for function h(x) as:

x    y

−2   14

−1   9

 0   6

  1   5

 2   6

 3   9

 4   14

Hence, the minimum value attained by h(x) is 5. ( when x=1)

  • Also we are given function g(x) ; a quadratic function passing through (2,7),(3,6) and (4,7)

so, the equation will be:

g(x)=ax^2+bx+cHence on putting these coordinates we will get:

a=1,b=3 and c=7.

Hence the function g(x) is given as:

g(x)=x^2-6x+15

So,the minimum value attained by g(x) could be seen from the graph is at the point (3,6).

Hence, the minimum value attained by g(x) is 6.

Hence the function which has the smallest minimum is h(x)

6 0
3 years ago
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