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guapka [62]
3 years ago
7

The slope of the line that passes through the point (17,20) and (1,-8) is

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

y = m x + b      standard form of equation for straight line\

        m = (y2 - y1) / (x2 - x1) = (20 - -8) / 17 - 1) = 28 / 16

        m = 7 / 4

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Make a table of values and graph the solutions of the given equation.
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Answer: 3
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3 years ago
15v − -14v − -14 = -15 solve for v ps..... help plz
Alchen [17]

Solve for  v  by simplifying both sides of the equation, then isolating the variable.

v = -1

5 0
3 years ago
We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
3 years ago
How many times can 2 go into 245 in fraction form​
zzz [600]

Answer:

244 1/1

Step-by-step explanation:

Since 2 goes into 245 122 times with 1 left over, it would be 244 and a whole, it would probably just be 244 and 1/1 or 245 but you asked for fraction so 244 1/1

5 0
3 years ago
A count went up from 450 to 600. What was the approximate percent increase
hram777 [196]

Answer:

33.33%

Step-by-step explanation:

do 600 minus 450 to find the increase

then 150/450 u have to simplify them

which equals to 1/3

1/3 = ?/100

100 times 1 divided by 3

4 0
3 years ago
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