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lana66690 [7]
3 years ago
10

The function y=(-1/2)x - 6 was the result of shifting the graph S units down. Find the following.

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

X is 9

axis 2 north

roots 2/1

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Negative one minus negative seven times volume plus three equals BLANK. If v is a variable, the question is wrong.
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Five years ago ,a father was four times as old as his son.In five years time the father will be twice as old as the son.If x and
andrew-mc [135]
B 4y-y=15;x-2y=5 is the correct one
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3 years ago
Solve the system of equations below. <br> 5x + 2y = 9<br> 2x - 3y = 15
riadik2000 [5.3K]

Answer:

(3,-3)

y= -3

x= 3

Step-by-step explanation:

5x+2y=9

2x-3y=15

solve the equation

x=9/5-2/5y

2x-3y=15

substitute the value of x into an equation

2(9/5-2/5y)-3y=15

distribute

18/5-4/5y-3y=15

subtract -4/5 to -3

18/5-19/5y=15

subtract 18/5 from both sides

-19/5=57/5

divide both sides by -19/5

y= -3

substitute the value of y into an equation

x=9/5-2/5(-3)

distribute

x=9/5+6/5

add 9/5 to 6/5

x=3

--------

(3,-3)

--------

3 0
4 years ago
What is 59% of 14 m?
sergiy2304 [10]

That would be 8.26 meters.

3 0
3 years ago
Pls solve the simultaneous equation in the attachment.
siniylev [52]

Answer:

Part a) The solution is the ordered pair (6,10)

Part b) The solutions are the ordered pairs (7,3) and (15,1.4)

Step-by-step explanation:

Part a) we have

\frac{x}{2}-\frac{y}{5}=1 ----> equation A

y-\frac{x}{3}=8 ----> equation B

Multiply equation A by 10 both sides to remove the fractions

5x-2y=10 ----> equation C

isolate the variable y in equation B

y=\frac{x}{3}+8 ----> equation D

we have the system of equations

5x-2y=10 ----> equation C

y=\frac{x}{3}+8 ----> equation D

Solve the system by substitution

substitute equation D in equation C

5x-2(\frac{x}{3}+8)=10

solve for x

5x-\frac{2x}{3}-16=10

Multiply by 3 both sides

15x-2x-48=30

15x-2x=48+30

Combine like terms

13x=78

x=6

<em>Find the value of y</em>

y=\frac{x}{3}+8

y=\frac{6}{3}+8

y=10

The solution is the ordered pair (6,10)

Part b) we have

xy=21 ---> equation A

x+5y=22 ----> equation B

isolate the variable x in the equation B

x=22-5y ----> equation C

substitute equation C in equation A

(22-5y)y=21

solve for y

22y-5y^2=21

5y^2-22y+21=0

Solve the quadratic equation by graphing

The solutions are y=1.4, y=3

see the attached figure

<em>Find the values of x</em>

For y=1.4

x=22-5(1.4)=15

For y=3

x=22-5(3)=7

therefore

The solutions are the ordered pairs (7,3) and (15,1.4)

3 0
4 years ago
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