Answer:
The price of a Dinner= $6.22
Explanation:
<em>Mark-up is the proportion of the product cost which is expected to be made as profit. In other words, it is profit expressed as a percentage of product cost.</em>
To account for the spoilage rate of 10%, $3.50 unit cost would be consider as 90% of the cost. Thus, 100% of the cost would be given as follows:
Dinner cost = 100/(100-10)× 3.50= 3.89
The price of a Dinner = product cost + 60% of product cost
The price of a Dinner = 3.89 + 60%*3.89= $6.22
The price of a Dinner= $6.22
Answer: Option B
Explanation: The receiving of cash from customers will have no effect on total assets, as the amount of inventory will decrease and the amount of cash will increase by the same amount. Thus the accounting equation will remain same from such a transaction as one asset will decrease and other will increase.
Thus, from the above we can conclude that the correct option is B.
Answer:
(a)
For Job G15:
Direct labor = $20,000
Overhead applied = 16,000
Overhead rate = 
= 0.8 × 100
= 80%
Overhead applied = Direct labor × 80%
= $20,000 × 80%
= $16,000
Overhead is applied on direct labor. Hence, rate is 80%.
Overhead for Job B10 = Direct labor × 80%
= $54,000 × 80%
= $43,200
Therefore,
Total overhead applied = $43,200 + 45,750 + 16,000
= $104,950
(b) Hence,
Overapplied overhead for February:
= Total overhead applied - Actual Overhead
= $104,950 - $68,500
= $36,450
Answer:
It is 6.58%
Explanation:
Debt-Equity Ratio = Debt/Equity
0.68= Debt/358,200
Debt = 0.68 x 358,200
Debt = $243,576
Total Asset Turnover = Revenue/ Total Asset
Total Assets = Debt + Equity = $243,576+ $358,200=$601,776
1.2= Revenue/601,776
Revenue= 1.2 x 601,776
=$722,131.20
Profit Margin = Net income/ Revenue x 100%
= $47,500/$722,131.20 x100%
= 6.58%
