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3 years ago

A population is currently

Mathematics

1 answer:

n200080 [17]3 years ago

5 0

Answer:

Step-by-step explanation:

The current world population is 7.9 billion as of July 2021 according to the most recent United Nations estimates elaborated by Worldometer. The term "World Population" refers to the human population (the total number of humans currently living) of the world.

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A line intersects the points(-22,-14) and (-18,-12). What is the slope-intercept equation for this line?

zaharov [31]

Hello there,

Well we are going to start off with the equation to find the slope based on the given points:

$\frac{y_{2} - y_{1} }{x_{2} -x_{1} }$

Now using the two given points we are going to plug in and solve:

$\frac{(-12)-(-14)}{(-18)-(-22)}$ = $\frac{2}{4}$ = $\frac{1}{2}$

From this you know that $\frac{1}{2}$ is the slope of the equation. However, to find the y-intercept we are going to use y = mx+ b and plug in one of the points to solve:

(-14) = $\frac{1}{2}$ (-22) + b

(-14) = (-11) + b

-3 = b

That means that the y-intercept is at (0, -3). Lastly, we are just going to plug all this into the slope-intercept form:

y = $\frac{1}{2}$ - 3

Hope I helped,

Amna

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3 years ago

Can anyone help me with this math stuff? :p

Mars2501 [29]

Answer:

if the recipe makes 48 cookies and the serving size is 3 then you should actually can just make the regular recipe and have 9 cookies leftover

Step-by-step explanation:

7 0

3 years ago

Expand (2x+2)^6<br> How would you find the answer using the binomial theorem?

Yanka [14]

Answer:

Step-by-step explanation:

$\displaystyle\\\sum\limits _{k=0}^n\frac{n!}{k!*(n-k)!}a^{n-k}b^k .\\\\k=0\\\frac{n!}{0!*(n-0)!}a^{n-0}b^0=C_n^0a^n*1=C_n^0a^n.\\\\ k=1\\\frac{n!}{1!*(n-1)!} a^{n-1}b^1=C_n^1a^{n-1}b^1.\\\\k=2\\\frac{n!}{2!*(n-2)!} a^{n-2}b^2=C_n^2a^{n-2}b^2.\\\\k=n\\\frac{n!}{n!*(n-n)!} a^{n-n}b^n=C_n^na^0b^n=C_n^nb^n.\\\\C_n^0a^n+C_n^1a^{n-1}b^1+C_n^2a^{n-2}b^2+...+C_n^nb^n=(a+b)^n.$

$\displaystyle\\(2x+2)^6=\frac{6!}{(6-0)!*0!} (2x)^62^0+\frac{6!}{(6-1)!*1!} (2x)^{6-1}2^1+\frac{6!}{(6-2)!*2!}(2x)^{6-2}2^2+\\\\ +\frac{6!}{(6-3)!*3!} (2a)^{6-3}2^3+\frac{6!}{(6-4)*4!} (2x)^{6-4}b^4+\frac{6!}{(6-5)!*5!}(2x)^{6-5} b^5+\frac{6!}{(6-6)!*6!}(2x)^{6-6}b^6. \\\\$

$(2x+2)^6=\frac{6!}{6!*1} 2^6*x^6*1+\frac{5!*6}{5!*1}2^5*x^5*2+\\\\+\frac{4!*5*6}{4!*1*2}2^4*x^4*2^2+ \frac{3!*4*5*6}{3!*1*2*3} 2^3*x^3*2^3+\frac{4!*5*6}{2!*4!}2^2*x^2*2^4+\\\\+\frac{5!*6}{1!*5!} 2^1*x^1*2^5+\frac{6!}{0!*6!} x^02^6\\\\(2x+2)^6=64x^6+384x^5+960x^4+1280x^3+960x^2+384x+64.$

8 0

2 years ago

PLEASE HELP APAP, WILL MARK BRAINLIEST WHEN POSSIBLE! The length of a rectangle is shown below:

prisoha [69]

Im pretty sure the correct answer is the fourth one

6 0

3 years ago

Read 2 more answers

part of the river she observed fell 1.68 millimeters per year for 1.5 years. Use the distributive property to calculate the exac

Alecsey [184]

1.68 mm per year for 1.5 years could be rewritten as
(2.00-0.32) mm per year for 1.5 yrs.

Multiply: (1.5 yrs)(2.00-0.32)(mm/yr) = 3 mm + 0.48 mm = 3.48 mm

This approach makes use of the distributive property of multiplication.

8 0

4 years ago