Answer:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
Step-by-step explanation:
1) We set up our null and alternative hypothesis as
H0: proportion of fatal bicycle accidents in 2015 was the same for all days of the week
against the claim
Ha: proportion of fatal bicycle accidents in 2015 was not the same for all days of the week
2) the significance level alpha is set at 0.05
3) the test statistic under H0 is
χ²= ∑ (ni - npi)²/ npi
which has an approximate chi square distribution with ( n-1)=7-1= 6 d.f
4) The critical region is χ² ≥ χ² (0.05)6 = 12.59
5) Calculations:
χ²= ∑ (16- 14.28)²/14.28 + (12- 14.28)²/14.28 + (12- 14.28)²/14.28 + (13- 14.28)²/14.28 + (14- 14.28)²/14.28 + (15- 14.28)²/14.28 + (18- 14.28)²/14.28
χ²= 1/14.28 [ 2.938+ 5.1984 +5.1984+1.6384+0.0784 +1.6384+13.84]
χ²= 1/14.28[8.1364]
χ²= 0.569= 0.57
6) Conclusion:
The calculated χ² = 0.57 does not fall in the critical region χ² ≥ 12.59 so we fail to reject the null hypothesis and conclude the proportion of fatal bicycle accidents in 2015 was the same for all days of the week.
b.<u> It is r</u>easonable to conclude that the proportion of fatal bicycle accidents in 2015 was the same for all days of the week
Answer:
- Doug's garden: 87 lbs
- Kelsey's garden: 15 lbs
Step-by-step explanation:
Let k represent the pounds of produce coming from Kelsey's garden. Then Doug's garden produces 5.8k pounds of produce, and the total weight of it is ...
k + 5.8k = 102
6.8k = 102 . . . . . . . . . . . simplify
k = 102/6.8 = 15 . . . . . . pounds of produce from Kelsey's garden
5.8k = 5.8·15 = 87 . . . . pounds of produce from Doug's garden
Answer:
y = (1/6)x - 5
Step-by-step explanation:
Substituting m for the the slope:
y = (1/6)x + b
Plugging in the values showed in the point (x = 12, y = -3):
-3 = (1/6)12 + b
-3 = 2 + b
b = -5
y = (1/6)x - 5
Hope this helps!
Like I said above, There were 40 rolls, 6 of which were a two (6/40) and 8 of which were a 4 (8/40). Simply add these together to get 14/40 as the probability of rolling a 2 or 4. This simplifies to 7/20
Answer:
C. 49
Step-by-step explanation:
Start by filling in your values.
Solve using PEMDAS.
49 + 99 / 11 - 9
49 + 9 - 9
58 - 9
49
