The y-intercepts are
(0,0) and (5,0)
The equation of the quadratic function is
f(t) = at(t-5)
Solving for a
12 = a(3)(3-5)
a = -2
The equation of the quadractic function is
f(t) = -2t(t -5)
f(t) = -2t² + 10t<span />

3 0

3 years ago

Read 2 more answers

Write an expression for the operation described."5 divided by the product of 3 and 2"A) (5 ÷ 3) × 2B) 5 ÷ (3 × 2)C) 3 × (2 ÷ 5)D

Alex787 [66]

5 / (3x2) hope this helps!! (the slash is a division sign)

6 0

2 years ago

Need help with this math problem

Andre45 [30]

Hey There!

First you would need to factor out the two.

-4x^3/2 = -2x^3

2x^2/2= x^2

12x/2= 6x

6/2= 3

Now we have.

-2x^3+x^2+6x+3 / x+1

We would then factor with polynomial division, and then we should have.

-2(2x^2 - 3x - 3)(x+1) / x+1

We would then cancel out the x+1

Therefore, the answer would be $\boxed{-2(2x^2-3x-3)}$

Hope this helped!

8 0

3 years ago