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ira [324]
3 years ago
10

A soccer ball is kicked into the air, and its path can be modeled with a quadratic function. The table shows the time, t, in sec

onds, and the height of the soccer ball, h, in feet. Follow the steps to write the function. 1. Identify x-intercepts: (0, 0) and (5, 0) 2. Use factored form: f(t) = a(t − 0)(t − 5) f(t) = at(t − 5) 3. Find the value of: 12 = a(3)(3 − 5) 4. Write function: f(t) = t(t −)
Mathematics
2 answers:
vfiekz [6]3 years ago
5 0

The answers -2 and 5

yaroslaw [1]3 years ago
3 0
The y-intercepts are
(0,0) and (5,0)
The equation of the quadratic function is
f(t) = at(t-5)
Solving for a
12 = a(3)(3-5)
a = -2
The equation of the quadractic function is
f(t) = -2t(t -5)
f(t) = -2t² + 10t<span />
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Elden [556K]
If f(x)=e^x-1 +5 and g(x) is a transformation or, the same thing just moved, and its y-intercept is -3 then its equation would be:

D) g(x)=e^x-1 -3
8 0
3 years ago
I need help I’m not sure
Daniel [21]

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad  (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 +  x_1}{2}~~~ ,~~~ \cfrac{ y_2 +  y_1}{2} \right) \\\\\\ \left( \cfrac{-6+3}{2}~~,~~\cfrac{-6+5}{2} \right)\implies \left(\cfrac{-3}{2}~~,~~\cfrac{-1}{2}  \right)\implies \left( -1\frac{1}{2}~,~-\frac{1}{2} \right)

3 0
3 years ago
Solve two sevenths times four sixths . (2 points) Group of answer choices six forty seconds eight forty seconds six thirteenths
Maksim231197 [3]

Given:

The statement is "two sevenths times four sixths".

To find:

The value of the product.

Solution:

Two sevenths times four sixths can be written as:

\dfrac{2}{7}\times \dfrac{4}{6}

It can be rewritten as:

\dfrac{2}{7}\times \dfrac{4}{6}=\dfrac{2\times 4}{7\times 6}

\dfrac{2}{7}\times \dfrac{4}{6}=\dfrac{8}{42}

The answer of given expression is eight forty seconds.

Therefore, the correct option is B.

8 0
3 years ago
I really need help with this, thank you!!!
Lyrx [107]

Answer:

6. 60°

7. 5.19559

8. 7.96011

Step-by-step explanation:

6. The sum of angles in a triangle is 180°, so the remaining angle is ...

  180° -40° -80° = 60°

7. The lengths of sides are proportional to the sine of the opposite angle (Law of Sines).

  a = c·sin(A)/sin(C) = 7·sin(40°)/sin(60°) ≈ 5.19559

8. Same explanation as 7.

  b = c·sin(B)/sin(C) = 7·sin(80°)/sin(60°) ≈ 7.96011  

3 0
3 years ago
Read 2 more answers
Researchers fed mice a specific amount of Dieldrin, a poisonous pesticide, and studied their nervous systems to find out why Die
Elodia [21]

Answer:

Step-by-step explanation:

Part A

Mean = (2.2 + 2.4 + 2.5 + 2.5 + 2.6 + 2.7)/6 = 2.48

Standard deviation = √(summation(x - mean)²/n

n = 6

Summation(x - mean)² = (2.2 - 2.48)^2 + (2.4 - 2.48)^2 + (2.5 - 2.48)^2 + (2.5 - 2.48)^2 + (2.6 - 2.48)^2 + (2.7 - 2.48)^2 = 0.1484

Standard deviation = √(0.1484/6

s = 0.16

Standard error = s/√n = 0.16/√6 = 0.065

Part B

Confidence interval is written as sample mean ± margin of error

Margin of error = z × s/√n

Since sample size is small and population standard deviation is unknown, z for 98% confidence level would be the t score from the student t distribution table. Degree of freedom = n - 1 = 6 - 1 = 5

Therefore, z = 3.365

Margin of error = 3.365 × 0.16/√6 = 0.22

Confidence interval is 2.48 ± 0.22

Part C

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

H0: µ = 2.3

For the alternative hypothesis,

H1: µ > 2.3

This is a right tailed test

Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 6

Degrees of freedom, df = n - 1 = 6 - 1 = 5

t = (x - µ)/(s/√n)

Where

x = sample mean = 2.48

µ = population mean = 2.3

s = samples standard deviation = 0.16

t = (2.48 - 2.3)/(0.16/√6) = 2.76

We would determine the p value using the t test calculator. It becomes

p = 0.02

Assuming significance level, alpha = 0.05.

Since alpha, 0.05 > than the p value, 0.02, then we would reject the null hypothesis. Therefore, At a 5% level of significance, the sample data showed significant evidence that the mean absolute refractory period for all mice when subjected to the same treatment increased.

6 0
3 years ago
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