Need help with this math problem
1 answer:
Hey There!
First you would need to factor out the two.
-4x^3/2 = -2x^3
2x^2/2= x^2
12x/2= 6x
6/2= 3
Now we have.
-2x^3+x^2+6x+3 / x+1
We would then factor with polynomial division, and then we should have.
-2(2x^2 - 3x - 3)(x+1) / x+1
We would then cancel out the x+1
Therefore, the answer would be
Hope this helped!
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<u>Answer:</u>
<u>Step-by-step explanation:</u>
- Given a slope and a point on the line, you can use point slope form and then rearrage your terms into slope-intercept form
- <u>SLOPE-INTERCEPT FORM</u>:
, where "m" is your slope and "b" is your y-intercept
- <u>POINT-SLOPE FORM: </u>
, where
represents the y-coordinate of your point,
represents the x-coordinate of your point, and
represents the slope
- Point-slope form
- Slope-intercept form
Given the function
Consider the point (2, 56) i.e. when x = 2
Therefore, point (2, 56) lie on the graph of the given exponential function.
Consider the point (-2, -4) i.e. when x = -2
Therefore, point (-2, -4) lie on the graph of the given exponential function.
Consider the point (8, 0) i.e. when x = 8
Therefore, point (8, 0) does not lie on the graph of the given exponential function.
Consider the point (24, 1) i.e. when x = 24
Therefore, point (24, 1) does not lie on the graph of the given exponential function.
Consider the point (2, 56) i.e. when x = 2
Therefore, point (2, 56) lie on the graph of the given exponential function.
Consider the point (-2, -4) i.e. when x = -2
Therefore, point (-2, -4) lie on the graph of the given exponential function.
Consider the point (8, 0) i.e. when x = 8
Therefore, point (8, 0) does not lie on the graph of the given exponential function.
Consider the point (24, 1) i.e. when x = 24
Therefore, point (24, 1) does not lie on the graph of the given exponential function.