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alukav5142 [94]

3 years ago

10

Archeologists found a previously unknown pyramid in Central America, shown in the figure. The media is interested in the volume

of this pyramid. Find the volume of the pyramid.

1 answer:

german3 years ago

4 0

Answer: height of the pyramid is 52 m.

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Which point on the graph represents the y-intercept?

Eduardwww [97]

0,2 because the y intercept is th middle line so you go up the line and see what number the line goes through

5 0

4 years ago

Read 2 more answers

HELP!! Select the values for the domain and range of the functions graphed below.

Goryan [66]

Answer:

Graph 1

Domain = -8 =< x =< 10

Range = -9 =< f(x) =< 9

Graph 2

Domain = -1 =< x =< 5

Range = -1 =< f(x) =< 2

Explaination:

Domain means the inputed x values on the x-axis, so to make things simpler and to not write every individual x values. We write it with <, >, and =<. (you can see it as the 'width' of a graph).

Range means the output y values on the y-axis. It's like the 'height' of a graph. And also, to make things simpler and to not write every individual y values. We write it with <, >, and =< with f(x) too because f(x) = y.

3 0

2 years ago

In football, a completion percentage is the number of completions

Finger [1]

Ian has a higher passing percentage

3 0

3 years ago

The bike store marks up the wholesale cost of all of the bikes they sell by 30%.

aev [14]

Answer:

A ) The money which Andre pay for the bike is $ 67.30

B ) The money which Andre pay for the bike is $ 76.92

Step-by-step explanation:

Given as :

The wholesale cost or market price of the bike = m.p = $ 96.15

A ) The discount percentage = 30 %

Let The selling price of the bike after discount = s.p

Now ,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 30 % = 1 - $\dfrac{s. p }{m . p}$

or, $\dfrac{30 }{100}$ = 1 - $\dfrac{s. p }{96.15}$

Or, $\dfrac{s. p }{96.15}$ = 1 - $\dfrac{30 }{100}$

or, $\dfrac{s. p }{96.15}$ = $\dfrac{100 - 30 }{100}$

Or, $\dfrac{s. p }{96.15}$ = $\dfrac{70}{100}$

Or, s. p = $\dfrac{70}{100}$ × 96.15

∴ s.p = $ 67.305

So, He will pay $ 67.30

Hence The money which Andre pay for the bike is $ 67.30 . Answer

B ) If the bike is discounted by 20 % , let The selling price = s.p'

So,

Discount % = $\dfrac{m.p - s. p }{m . p}$

or, 20 % = 1 - $\dfrac{s. p' }{m . p}$

or, $\dfrac{20 }{100}$ = 1 - $\dfrac{s. p' }{96.15}$

Or, $\dfrac{s. p' }{96.15}$ = 1 - $\dfrac{20 }{100}$

or, $\dfrac{s. p' }{96.15}$ = $\dfrac{100 - 20 }{100}$

Or, $\dfrac{s. p' }{96.15}$ = $\dfrac{80}{100}$

Or, s. p' = $\dfrac{80}{100}$ × 96.15

∴ s.p' = $ 76.92

So, He will pay $ 76.92

Hence The money which Andre pay for the bike is $ 76.92 . Answer

7 0

3 years ago

A jeepney ride cost 11 pesos for the first 4 kilometers and each additional integer kilometers adds 3.50 pesos to the fare, use

Nookie1986 [14]

Answer:

$f(d)=\left\{ \begin{matrix} 11 & \text{for} & 0< d\leq 4 \\-3+3.5d & \text{for}& d > 4 \end$

Step-by-step explanation:

Cost of first 4 kilometers ride = 11 pesos.

So, for the first 4 km, the fair is constant i.e.

for 1 km the fare is 11 pesos,

for 2 km the fair is also 11 pesos,

similarly, for 3 km of 4 km, the fare is 11 pesos.

Hence, for the distance $0\geq d\geq 4$ , the fair function,

$f(d)=11\cdots(i)$

After 4 km, there is an increment of $ 3.50 for each kilometer.

So, the fare function up to 5 kilometers,

$f(d)=11+3.5=14.5$

So, the fare function up to 6 kilometers, i.e for the distance $5$ ,

$f(d)=11+2\times3.5=18$

This can be arranged as the fare function up to 6 km,

$f(d)=11+(6-4)\times3.5=18$

Similarly, the fare function up to $d$ kilometer $(n>4)$ ,

$f(d)=11+(d-4)\times3.5$

$\Rightarrrow f(d)=-3+3.5d\cdots(ii)$

Hence, from equations (i) and (ii),

$f(d)=\left\{ \begin{matrix} 11 & \text{for}\; 0< d \leq 4 \\-3+3.5d & \text{for}\; d > 4 \end$

8 0

3 years ago