Answer:
Triangle BCA and Triangle KIJ are congruent by SAS rule
Answer:
and 
Step-by-step explanation:
The equation of curve is

We need to find the equation of the tangent line to the curve at the point (-3, 1).
Differentiate with respect to x.
![2[2(x^2+y^2)\frac{d}{dx}(x^2+y^2)]=25(2x-2y\frac{dy}{dx})](https://tex.z-dn.net/?f=2%5B2%28x%5E2%2By%5E2%29%5Cfrac%7Bd%7D%7Bdx%7D%28x%5E2%2By%5E2%29%5D%3D25%282x-2y%5Cfrac%7Bdy%7D%7Bdx%7D%29)

The point of tangency is (-3,1). It means the slope of tangent is
.
Substitute x=-3 and y=1 in the above equation.





Divide both sides by 130.

If a line passes through a points
with slope m, then the point slope form of the line is

The slope of tangent line is
and it passes through the point (-3,1). So, the equation of tangent is


Add 1 on both sides.


Therefore,
and
.
Answer:
A = 192
Step-by-step explanation:
r = 16/2 = 8
A = 3x(8)^2
8^2 = 64
A = 3 x 64 = 192
Answer:
umm why not ask the teacher for help they will help you
Step-by-step explanation:
Answer:
19 and 2
Step-by-step explanation:
Let x represent the first number and y represents second number
x + y = 19
x - y = 17 add two equations up
2x = 36 divide both sides by 2
x = 19 and since the difference is 17 the other number is 2