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WINSTONCH [101]
3 years ago
11

Find the output, y, when the input, x, is -9

Mathematics
1 answer:
dusya [7]3 years ago
4 0

Answer

Step-by-step explanation:

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What is the value of x<br> What is the value of the exterior angle
Oduvanchick [21]

Answer:

???????

Step-by-step explanation:

triangles add to 180 degrees

lets call the unknown angle y

82 + x + y = 180

we also know that y + (2x-20 ) = 180  because it is a straight line

lets solve this for y

y + (2x-20 ) = 180

subtract (2x-20) from each side

y = 180 - (2x-20)

y = 180 - 2x + 20

y = 200 -2x

substitute this in the triangle equation

82 + x + y = 180

82 + x + 200 -2x = 180

combine like terms

282 -x = 180

subtract 282 from each side

-x = -102

multiply by -1 on each side

x = 102

the exterior angle is 2x-20

exterior angle is 2(102) -20

exterior angle is 204-20

exterior angle is 184

This is impossible.


There is a mistake with this problem

The triangle is not a triangle.  Angle y would be negative. y=-4

6 0
3 years ago
Plz help!!! marking brainiest!!
Ghella [55]
Answer: 3(x-12)(x+2)
5 0
3 years ago
Find the values of the six trigonometric functions of an angle in standard position if the point with coordinates (6,-5) lies on
Tom [10]
C i guesss because you just said it
4 0
3 years ago
What is slope between the points (-5,7) and (4,-8)?
WINSTONCH [101]
The slope can sometimes be called the gradient, and the equation for the gradient is (y2 - y1)/(x2 - x1). So therefore, you'd do: (-8 - 7)/(4 - -5) which is (-15)/9) which is -1 2/3 or -1.6 (recurring), which is your answer. I hope this helps! Let me know if I've confused you :)
3 0
3 years ago
A cube-shaped box has a volume of 1/8 of a cubic meter. What is the perimeter of each of its
belka [17]

Given:

The volume of a cube-shaped box is \dfrac{1}{8} cubic meter.

To find:

The perimeter of each of its faces.

Solution:

Let "a" be the side length of the cube shaped box. Then the volume of the box is:

V=(side)^3

V=a^3

It is given that the volume of a cube-shaped box is \dfrac{1}{8}  cubic meter.

a^3=\dfrac{1}{8}

Taking cube root on both sides, we get

a=\dfrac{1}{2}

Now, the perimeter of each face of a cube is:

P=4a

Where, a is the side length of the cube.

Putting a=\dfrac{1}{2}, we get

P=4\times \dfrac{1}{2}

P=2

Therefore, the perimeter of each face of a cube-shaped box is 2 meters.

5 0
3 years ago
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