Find two fractions that have product of 2/5.
1 answer:
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Answer:
First question: 1270
Second question: 4080
Step-by-step explanation:
Here is the Sum formula:
where n represents the number of terms, and
is the first term, and
is the last term.
Let's look at the first question:
k is the first number of the sequence, 5, and 20 is the last number of the sequence.
You can find the first term () by substituting k in the formula for 5.
3(5)+26=15+26=41
You can find the last term () by substituting k for 20 into the formula.
3(20)+26=60+26=86
now, knowing there are 20 terms in total, , and
, we can put it into the Sum formula.
Answer to the first question: 1270
Next question:
Even though the given formula uses n as the variable, this problem works the same way as the previous one.
Substitute n in the formula for k, which is 5 to find the first term: 14(5)+29=99
Substitute 20 for n to find the second term: 14(20)+29=309
Now assemble the Sum formula:
Answer to the second question: 4080