Yes. In the beginning, glycolysis requires 2 ATP molecules.
One ATP allows for the phosphorylation of the glucose molecule to fructose-6-phosphate and another phosphorylation to fructose-1,
6-biphosphate. The fructose-1, 6- bisphosphate
is then cleaved into two glyceraldehyde-3-phosphates that then enter the energy
generating part of the glycolysis biochemical reaction.
Answer:
2^3= 8 possible combinations
Explanation:
Mendel discovered in his experiments that a pair of chromosome in an organism consists of two similar but non-identical chromosomes called HOMOLOGOUS CHROMOSOMES in which each comes from each parent.
During meiosis, each homologous chromosomes get sorted into gametes in accordance to Mendel's law of segregation and independent assortment.
For each chromosome, a variant form of gene called allele is gets randomly sorted into gametes to form 8 possible combinations for an organism with three (3) pair of chromosomes.
Possible number of combination of gametes is determined by the formula 2^n, where n is the number of character or chromosome pair in this case.
Hence 2^3= 8 possible chromosomal combinations of gametes produced by meiosis.
Answer - 1,000 kcal/day
Given the situation above, Matthew should consume an extra <span>1,000 kcal per day in order </span>to regain to a healthy weight. This <span>will promote a two pound weight gain </span>per week. <span>Typically, one pound of fat weighs 3500 kcal, so it would takes </span>an extra<span> 3500 </span>calories<span> to gain one pound of body weight.</span>
The correct answer is C. Plasma~
Answer:
The black dogs are h o m ozygous with a dominant trait, but the brown dogs are h o m ozygous with a recessive trair. So if the dogs breed their offspring will all be black because black is dominant to brown, so therefore black is expressed.
Diagram is in the pic above
Blue box is black dog
Red box is brown dog
A is the allele for black
b is the allele for brown
A is dominant so b, so A is expressed