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3 years ago

2 times 2 times 13 what is the missing number

Mathematics

1 answer:

atroni [7]3 years ago

5 0

The answer is 52 if you are looking for the answer to 2x2x13=? then it is 52. Otherwise idk what you are asking.

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Find the three arithmetic means between -5 and -25.

inn [45]

The answer you are looking for is: -15.
I hope this helps.

7 0

3 years ago

A man walks at 60km/ hr. How long does he walks between 9:30 am and 12 noon

N76 [4]

Answer:

He walks 150 km in 2.5 hours.

Step-by-step explanation:

From 9:30 a.m. to noon, it's 2.5 hours.

distance = speed * time

distance = 60 km/h * 2.5 h

distance = 150 km

Answer: He walks 150 km in 2.5 hours.

3 0

2 years ago

What is the value of the expression shown 24-52

Ahat [919]

Answer:

-28

Step-by-step explanation:

It is negative so:

52-24=28

-28

8 0

3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

Which of the following situations could be represented by the expression - 14+ (- 7)?

RUDIKE [14]

Answer:

Matt's

Step-by-step explanation:

he has to give away $14 (-14)

and also $7 (-7)

The others have positive numbers.

4 0

3 years ago