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3 years ago

Describe how you would use a yardstick to measure a rug

1 answer:

6 0

Well first of this makes sense because you need to make sure your rug will fit. So anyways, first lay your rug out on a flat surface, grab your yardstick, lay it on the rug to find the length and then the width. you then know the size of your rug(assuming its square). You can do the same thing in the room you want it in.

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Si 14 lápices cuestan 30

katrin2010 [14]

Then one pencil costs about 2.14 cents.
Entonces un lápiz cuesta alrededor de 2.14 centavos.

8 0

3 years ago

The difference of the squares of two positive consecutive even integers is 84. Find the integers.

ziro4ka [17]

Answer:

The two integers are 20 and 22.

Step-by-step explanation:

Let x be the first integer.

$(x+2)^{2}-x^{2} = 84\\x^{2} +4x+4-x^{2} = 84\\4x = 80\\x = 20$

3 0

3 years ago

Multiply and simplify: –3x2y2 • x4 –3x5y2 9x5y2 –3x6y2 –3x5y6

Contact [7]

Answer:

Multiplying and simplifying the term $-3x^2y^2 \:.\: x^4$ we get $\mathbf{-3x^6y^2}$

Option C is correct option.

Step-by-step explanation:

We need to multiply and simplify: $-3x^2y^2 \:.\: x^4$

Simplifying the term:

$-3x^2y^2 \:.\: x^4$

While multiplying, the variables with same bases are multiplied: $a^m\:.\:a^n=a^{m+n}$

In the given question only x^2 and x^4 are variables with same bases, So we get:

$=-3(x^{2+4})y^2\\=-3x^6y^2$

So, multiplying and simplifying the term $-3x^2y^2 \:.\: x^4$ we get $\mathbf{-3x^6y^2}$

Option C is correct option.

4 0

3 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

3 years ago

The base of a triangle is given as 2b. The height of the triangle is given as 5b-7. Find an expressions for the area of the tria

Tcecarenko [31]

Answer:

Step-by-step explanation:

Area = 1/2 * 2b * (5b - 7)

Area = 1/2 * 2b * (5b - 7) = 24

b * (5b - 7) = 24

5b^2 - 7b = 24

5b^2 - 7b - 24= 0

(b- 3 )(5b + 8) = 0

b = 3 This the only solution that works. b can't be minus

The base is 2b or 2 * 3 = 6

4 0

2 years ago