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Mama L [17]
3 years ago
14

A student reads at a constant rate in her chapter book. this can be described by the equation y equals 1/2 x. The teacher recomm

ends that students read for 20 minutes each night. How many pages will the student complete?
In a really exciting part of the book the student read 18 pages in one sitting.for how many minutes did she read?
If the book is 245 Pages how many minutes will it take her to finish? ​
Mathematics
1 answer:
ArbitrLikvidat [17]3 years ago
5 0
........zzzzzzzzzzzzzzzzznendjdjdheeoei(&;&:
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Step-by-step explanation:

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there are about 100 million smartphones in the U.S. your teacher has one smartphone. what share of US smartphones does your teac
barxatty [35]
100 000 000 =  10^{8}

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3 0
3 years ago
Identify the translation of the figure with the vertices P(−4,−5), L(1,−7), and K(−9,8), along the vector <−6, 3>.
jarptica [38.1K]

Answer:

P ′(−10, −2), L ′(−5, −4), K ′(−15, 11)

Step-by-step explanation:

The translation vector, ⟨−6,3⟩, can be used to derive a rule for the translation of the coordinates: (x,y)→(x−6,y+3).

Apply the rule to translate each of the three preimage vertices to the image vertices.

P(−4,−5)→P'(−10,−2)

L(1,−7)→L'(−5,−4)

K(−9,8)→K'(−15,11)

Therefore, P'(−10,−2), L'(−5,−4), N'(−15,11) is the translation of the figure with the vertices P(−4,−5), L(1,−7), and K(−9,8), along the vector ⟨−6,3⟩.

4 0
2 years ago
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In problem solve the given differential equation by underdetermined coefficients y''-2y+y=xe^x
Alexus [3.1K]

Answer:

Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

Step-by-step explanation:

Given Differential Equation,

y"-2y'+y=xe^x ...............(1)

We need to solve the given differential equations using undetermined coefficients.

Let the solution of the given differential equation is made up of two parts. one complimentary solution and one is particular solution.

\implies\:y(x)=y_c(x)+y_p(x)

For Complimentary solution,

Auxiliary equation is as follows

m² - 2m + 1 = 0

( m - 1 )² = 0

m = 1 , 1

So,

y_c(x)=C_1e^x+c_2xe^x

Now for particular solution,

let y_p(x)=Ax^3e^x

y'=Ax^3e^x+3Ax^2e^x

y"=Ax^3e^x+6Ax^2e^x+6Axe^x

Now putting these values in (1), we get

Ax^3e^x+6Ae^2e^x+6Axe^x-2(Ax^3e^x+3Ax^2e^x)+Ax^3e^x=xe^x

Ax^3e^x+6Ae^2e^x+6Axe^x-2Ax^3e^x-6Ax^2e^x+Ax^3e^x=xe^x

6Axe^x=xe^x

6A=1

A=\frac{1}{6}

\implies\:y_p(x)=\frac{x^3e^x}{6}

Therefore, Solution is y(t)=C_1e^x+C_2xe^x+\frac{x^3e^x}{6}

8 0
3 years ago
How do I reduce 3 25/21
Nesterboy [21]
So 25 goes into 21 how many times? 1. Add that 1 to the 3 making 4.
Then how much is left over of the 25 & 21? 4.
Making it 4 4/21
4 0
3 years ago
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