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sammy [17]
2 years ago
13

Tell whether the events are

Mathematics
1 answer:
madam [21]2 years ago
7 0

Answer:

check on g00gle

Step-by-step explanation:

no one gonna answer

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Pls help me I’ll give out brainliest please dont answer if you don’t know
eimsori [14]

Answer:

$8.65

Step-by-step explanation:

1.25+4.75+2.50=8.5

8.5+0.056(5.6%)=8.65

8 0
2 years ago
What’s the answer please help
sp2606 [1]

Answer:

{121,144,169} X intersecting Y means common number between x and y set

5 0
2 years ago
Helppppp nowwwww please
andrew11 [14]
P = d - 5.50
The cost of buying materials will be subtracted from what he earns. Therefore, what’s left over is the profit
6 0
3 years ago
The coordinates of points M,N, and P are ....
Rainbow [258]

Answer:

(-1, -1) Let me know if the explanation didn't make sense.  

Step-by-step explanation:

If we graph the three points we can see what looks like a quadrilateral's upper right portion, so we need a point in the lower left.  This means M is only connected to N here and P is only connected to N.  So we want to find the slope of these two lines.

MN is easy since their y values are the same, the slope is 0.

NP we just use the slope formula so (y2-y1)/(x2-x1) = (-1-3)/(5-4) = -4.

So now we want a line from point M with a slope of -4 to intersect with a line from point P with a slope of 0.  To find these lines  weuse point slope form  for those two points.  The formula for point slope form is y - y1 = m(x-x1)

y-3 = -4(x+2) -> y = -4x-5

y+1 = 0(x-5) -> y = -1

So now we want these two to intersect.  We just set them equal to each other.

-1 = -4x -5 -> -1 = x

So this gives us our x value.  Now we can plug that into either function to find the y value.  This is super easy of we use y = -1 because all y values in this are -1, so the point Q is (-1, -1)

8 0
3 years ago
If angle 0 is in quadrant I, what is the value of
Brilliant_brown [7]

Answer:

the \: answer \: is \: c \:  =  -  \frac{ \sqrt{14} }{5}

Step-by-step explanation:

\sin^{2}0 + ( \frac{ \sqrt{11} }{5} ) ^{2}  = 1( \sin^{2}0 +  \cos^{2} 0 = 1)

{ \sin }^{2}0 +  \frac{11}{25} = 1   \\  { \sin }^{2}0 =  \frac{14}{25}

\sin0_{1} =  -  \frac{ \sqrt{14}}{5} while \sin0_{2} =  \frac{ \sqrt{14} }{5}

  • Therfore theta is QI
  • Therfore sin theta >0
  • therefore \:  \sin0 =  \frac{ \sqrt{14} }{5}
4 0
2 years ago
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