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3 years ago

What is the area of triangles in square yards

Mathematics

1 answer:

tia_tia [17]3 years ago

3 0

Answer:

37.625 square yards or 37⅝ square yards

Step-by-step explanation:

Area of the triangle = ½*base*height

Where,

base = 10¾ yd = 10.75 yds

height = 7 yds

Substitute the value of each variable into the equation:

Area = ½*10.75*7

Area = 37.625 square yards or 37⅝ square yards

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Prove:1/sin²A-1/tan²A=1

Anit [1.1K]

Step-by-step explanation:

1/sin^2A -cos^2A/sin^2 A. ~tan = sin/cos

(1-cos^2)/sin^2A. ~ take lcm

sin^2A/sin^ A. ~ 1-cos^2A = sin^2A

for more free ans check bio

7 0

3 years ago

Read 2 more answers

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

3 years ago

Read 2 more answers

Solve the equation for y.<br> cy + 11 = f<br><br> Can someone help me?!

Ad libitum [116K]

Answer:

y=f−11/c

Step-by-step explanation:

cy+11=f

Step 1: Add -11 to both sides.

cy+11+−11=f+−11

cy=f−11

Step 2: Divide both sides by c.

cy/c=f−11/c

y=f−11/c

Answer:

y=f−11/c i think

4 0

3 years ago

A recipe calls for 2 3/4 cups of milk. if the recipe is tripled, how much milk is needed?

SSSSS [86.1K]

To be tripled means to be multiplied by 3. So multiply 2 3/4 by 3
2 3/4*3=8 1/4
Therefore the amount of milk needed is 8 1/4 cup

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3 years ago

Safari isn’t helping so plz help!!

aleksandr82 [10.1K]

Answer:

f(x)=2 cos(x)-1

Step-by-step explanation:

that is the answer

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3 years ago