All categories

2 years ago

What is the area of triangles in square yards

Mathematics

1 answer:

tia_tia [17]2 years ago

3 0

Answer:

37.625 square yards or 37⅝ square yards

Step-by-step explanation:

Area of the triangle = ½*base*height

Where,

base = 10¾ yd = 10.75 yds

height = 7 yds

Substitute the value of each variable into the equation:

Area = ½*10.75*7

Area = 37.625 square yards or 37⅝ square yards

You might be interested in

Drag the tiles to list the sides of △MNO from shortest to longest.

sweet [91]

The smaller the angle subtended by a side, the smaller the length of the

side.

The correct responses are;

Question 1: The list of sides from shortest to longest are;

MO/Shortest MO/Medium and MO/Longest

a) Friday

b) 70 minutes

c) 40%

d) Yes, the sum of the mean number of minutes spent on aerobic training and the mean number of minutes spent on strength training is equal to the mean total number of minutes spent training.

From the given diagram, we have, the measure of the third angle, ∠O, is

found as follows;

∠O = 180° - 54° - 61° = 65°

Therefore, ∠O = The largest angle

We get;

The longest side is opposite the largest angle, which gives;

The shortest side is the side opposite ∠N (54°)= $\frac{}{MO}$

The next shortest side is the side opposite ∠M(61°) = $\frac{}{NO}$

The longest side is the side opposite ∠O(65°) = $\frac{}{MN}$

a) The time spent training on Tuesday = 60 + 10 = 70 minutes

The time spent training on Thursday = 50 + 30 = 80 minutes

The time spent training on Friday = 45 + 40 = 85 minutes

Therefore, the day the athlete spent the longest total amount of time training is on Friday

b) The time spent training on Monday = 10 + 20 = 30 minutes

The time spent training on Wednesday = 20 + 15 = 35 minutes

Therefore, we get;

30, 35, 70, 80, and 85

The median total number of minutes the athlete spent training each day = 70 minutes

c) The time spent strength training = 20 + 10 + 15 + 30 + 45 = 120

The total number of minutes the athlete spent training = 70 + 80 + 85 + 30 + 35 = 300

$The$ $percentage$ $spent$ $on$ $strength$ $training$ = $\frac{120}{300}$ × $100 =$ $\frac{40}$ %

d) The mean number of minutes spent on strength training is found as follows;

$Mean_{strength} =\frac{120}{5} =24$

The mean number of minutes spent on aerobic training is found as follows;

$Mean_{aerobic} =\frac{10+60+20+50+40}{5} =36$

$Mean_{strength} +Mean_{aerobic} =24+36=60$

The mean total number of minutes spent training, $Mean_{total}$ = $\frac{300}{5}$ = 60

Therefore;

$Mean_{strength}+Mean_{aerobic} = Mean_{total} \\$

Learn more here:

brainly.com/question/2962546

4 0

2 years ago

HELP ME BEFORE I DIE!

KonstantinChe [14]

Answer:

0.6 or $\frac{3}{5}$

Step-by-step explanation:

Using the Pythagorean theorem ( $a^{2} +b^{2} =c^{2}$ ) we get that the hypotenuse is 5.

so the cos V is adjacent over the hypotenuse. so if adjacent is 3 and hypotenuse is 5, the answer is $\frac{3}{5}$ which equals 0.6 in decimal form.

3 0

3 years ago

Robert is writing a paper for language arts class. He can write 2/3 of a page in 1/4 of an hour. At what rate is Robert writing?

Irina-Kira [14]

Answer:

A) 2 2/3 pages per hour

Step-by-step explanation:

You would multiply 1/4 times 4 to get 1 hour

then you would multiply 2/3 times 4 which is 2 2/3

6 0

2 years ago

Cooper is a salesperson who sells computers at an electronics store. He makes a base pay amount of $60 per day regardless of sal

VikaD [51]

Answer: p= 1.25x + 70

5 0

2 years ago

Using the unit circle, determine the value of cos(-150°).

elena-14-01-66 [18.8K]

<h3>Answer: $-\frac{\sqrt{3}}{2}$ </h3>

Explanation:

The identity we'll use is cos(-x) = cos(x) for any value of x.

So cos(-150) = cos(150).

Then locate the angle 150 on the unit circle. The terminal point is $\left(-\frac{\sqrt{3}}{2}, \frac{1}{2}\right)$

The x coordinate of this terminal point is the value of cos(150).

5 0

3 years ago

Read 2 more answers