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3 years ago

Select the correct answer.

Mathematics

1 answer:

masya89 [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Either try all the numbers and see which ones work or do the following.

Times both sides by 2x-5.

3=x(2x-5)=2x^2-5x

Rearrange and solve the quadratic. I will factorise.

2x^2-5x-3=0

(2x+1)(x-3)=0

so x = -1/2 or 3

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What is the equation, in slope-intercept form, of the line

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Given that the graph of the equation of the line.

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We need to determine the equation of the line perpendicular to the given line.

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The slope of the given line can be determined by substituting any two coordinates from the line in the slope formula,

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting the coordinates (-1,3) and (2,2), we get;

$m_1=\frac{2-3}{2+1}$

$m_1=-\frac{1}{3}$

Thus, the slope of the given line is $m_1=-\frac{1}{3}$

Slope of the perpendicular line:

The slope of the perpendicular line can be determined by

$m_2=-\frac{1}{m_1}$

Substituting $m_1=-\frac{1}{3}$ , we get;

$m_2=-\frac{1}{-\frac{1}{3}}$

simplifying, we get;

$m_2=3$

Thus, the slope of the perpendicular line is 3.

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The equation of the perpendicular line can be determined using the formula,

$y-y_1=m(x-x_1)$

Substituting $m=3$ and the point (2,-1) in the above formula, we have;

$y+1=3(x-2)$

$y+1=3x-6$

$y=3x-7$

Thus, the equation of the perpendicular line is $y=3x-7$

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