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3 years ago

Select the correct answer.

Mathematics

1 answer:

masya89 [10]3 years ago

6 0

Answer:

Step-by-step explanation:

Either try all the numbers and see which ones work or do the following.

Times both sides by 2x-5.

3=x(2x-5)=2x^2-5x

Rearrange and solve the quadratic. I will factorise.

2x^2-5x-3=0

(2x+1)(x-3)=0

so x = -1/2 or 3

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C = .25t +3.50 in 'C' dollars for 't' minutes. How much does it cost to rent the canoe for 1 hour?

yKpoI14uk [10]

Answer and Step-by-step explanation:

We know that t is in minutes, and 1 hours is equal to 60 minutes, so we plug in 60 for t.

C = 0.25(60) + 3.50

C = 15 + 3.50

C = 18.50

<em><u>The cost to rent the canoe is $18.50.</u></em>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

8 0

2 years ago

Read 2 more answers

Daniel hosted a party in which 15 to 45 people could attend and he charged $7 per person for admission. What is the range of adm

irina [24]

Answer:

c. [105,315]

Step-by-step explanation:

6 0

3 years ago

How does the graph of f(x)=3lx+2l+4 relate to its parent function?

Sergeeva-Olga [200]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template above in mind, let's see this one

$\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}$

A=3, B=1, shrunk by AB or 3 units, about 1/3
C=2, horizontal shift by C/B or 2/1 or just 2, to the left
D=4, vertical shift upwards of 4 units

check the picture below

7 0

3 years ago

The bearing of a from b is 067 degrees. what is the bearing of b from a?

Zigmanuir [339]

In this case since 067 is less than 180, 180 will be added to it to find the bearing of b from a.
067+180=247
the bearing of b from a is 247
or
subtract 067 from 360
360-067=293
I am not sure of the right answer but I hope this helps.

6 0

3 years ago

A card is picked from a standard deck of 52 cards. Determine the odds against and the odds in favor of selecting a red face card

timama [110]

<h3>The probability of picking a red face card from the deck is $(\frac{3}{26} )$ </h3><h3>The probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$ </h3>

Step-by-step explanation:

The total number of cards in the deck = 52

The total number of red( Diamond + Hearts) face cards in the given deck

= 2 Red Queens + 2 Red jacks + 2 Red kings = 6 cards

Let E : Event of picking a red face card from the deck

Now , P( any event) = $\frac{\textrm{The number of favorable observations}}{\textrm{Total number of observations}}$

So, here P(Picking a red face card) = $\frac{\textrm{The number of red face cards}}{\textrm{Total number of cards}} = (\frac{6}{52} ) = (\frac{3}{26})$

Hence, the probability of picking a red face card from the deck is $(\frac{3}{26} )$

Now, as we know P (any event NOT A) = 1 - P(any event A)

So, P(NOT Picking a red face card) = 1 - P(Picking a red face card)

$= 1 - (\frac{3}{26} ) = \frac{26-3}{26} = (\frac{23}{26})$

Hence, the probability of NOT picking a red face card from the deck is $(\frac{23}{26} )$

8 0

3 years ago