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Rudiy27
3 years ago
14

Why could the mean of the data set below be misleading? 10 points! <3

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

the mean can be misleading, because there outlier (77), which is not close to the ages of the others, thereby changing the mean drastically.

hope this helps

strojnjashka [21]3 years ago
5 0

The mean or average of the data set would be misleading because there is an outlier, meaning that one of the numbers is either significantly lower or higher than the rest. That can be seen here because of the number 77.

Mean with ALL numbers : 35.3

Mean with all EXCEPT outlier : 27.6

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Phil earns $9.50 an hour
shtirl [24]
$9.50x45=$427.50(work per week)

$427.50-$55=$372.50(amount of money he earns per week)

$372.50x4x12=$17880(1 month has 4 weeks and 1 year has 12 months)

Answer: $17880
6 0
3 years ago
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7.2<br> 8.3<br> 152 in^3<br> What is the correct answer
san4es73 [151]

Answer:

1094.4

Step-by-step explanation:

assuming you want volume

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2 years ago
Consider the parabola given by the equation: f(x) = 4x² - 6x - 8 Find the following for this parabola: A) The vertex: Preview B)
jeyben [28]

Answer:

The vertex: (\frac{3}{4},-\frac{41}{4} )

The vertical intercept is: y=-8

The coordinates of the two intercepts of the parabola are (\frac{3+\sqrt{41} }{4} , 0) and (\frac{3-\sqrt{41} }{4} , 0)

Step-by-step explanation:

To find the vertex of the parabola 4x^2-6x-8 you need to:

1. Find the coefficients <em>a</em>, <em>b</em>, and <em>c </em>of the parabola equation

<em>a=4, b=-6, \:and \:c=-8</em>

2. You can apply this formula to find x-coordinate of the vertex

x=-\frac{b}{2a}, so

x=-\frac{-6}{2\cdot 4}\\x=\frac{3}{4}

3. To find the y-coordinate of the vertex you use the parabola equation and x-coordinate of the vertex (f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c)

f(-\frac{b}{2a})=a(-\frac{b}{2a})^2+b(-\frac{b}{2a})+c\\f(\frac{3}{4})=4\cdot (\frac{3}{4})^2-6\cdot (\frac{3}{4})-8\\y=\frac{-41}{4}

To find the vertical intercept you need to evaluate x = 0 into the parabola equation

f(x)=4x^2-6x-8\\f(0)=4(0)^2-6\cdot 0-0\\f(0)=-8

To find the coordinates of the two intercepts of the parabola you need to solve the parabola by completing the square

\mathrm{Add\:}8\mathrm{\:to\:both\:sides}

x^2-6x-8+8=0+8

\mathrm{Simplify}

4x^2-6x=8

\mathrm{Divide\:both\:sides\:by\:}4

\frac{4x^2-6x}{4}=\frac{8}{4}\\x^2-\frac{3x}{2}=2

\mathrm{Write\:equation\:in\:the\:form:\:\:}x^2+2ax+a^2=\left(x+a\right)^2

x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=2+\left(-\frac{3}{4}\right)^2\\x^2-\frac{3x}{2}+\left(-\frac{3}{4}\right)^2=\frac{41}{16}

\left(x-\frac{3}{4}\right)^2=\frac{41}{16}

\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}

x_1=\frac{\sqrt{41}+3}{4},\:x_2=\frac{-\sqrt{41}+3}{4}

4 0
3 years ago
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Answer:

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iren [92.7K]

log was used calculate big numbers before calculators

log is a re-arranged way to show a number with an exponent

example

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logx(Z) = y means x^y=Z

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(log(x-6)+ log(x))/log(2) = 4

(log(x-6)+ log(x)) = 4log(2)

(log(x-6)x) = log(16)

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