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Rudiy27
3 years ago
14

Why could the mean of the data set below be misleading? 10 points! <3

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

the mean can be misleading, because there outlier (77), which is not close to the ages of the others, thereby changing the mean drastically.

hope this helps

strojnjashka [21]3 years ago
5 0

The mean or average of the data set would be misleading because there is an outlier, meaning that one of the numbers is either significantly lower or higher than the rest. That can be seen here because of the number 77.

Mean with ALL numbers : 35.3

Mean with all EXCEPT outlier : 27.6

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I think that to find the volume , you just need to do:
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A class of 30 swim team members took a lifesaving test. Eighteen of the members had an average score of 92 points. The remaining
inysia [295]

Answer:

88.8%

Step-by-step explanation:

1.) 30-18= 12 which is the number of member that had an average of 84

2.)Then multiply  12 times 84 = 1008

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4.)Add 1008 and 1656 together  and get 2664.

5.)Divide 2664 / 30 and you get the average of 88.8

Hope this helps :)

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3 years ago
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galina1969 [7]
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3 years ago
A Ferris Wheel 22.0m in diameter rotates once every 12.5s. What is the ratio of a persons apperenet weight to her real weight (a
AnnZ [28]
  <span>Acceleration of a passenger is centripetal acceleration, since the Ferris wheel is assumed at uniform speed: 
a = omega^2*r 

omega and r in terms of given data: 
omega = 2*Pi/T 
r = d/2 

Thus: 
a = 2*Pi^2*d/T^2 

What forces cause this acceleration for the passenger, at either top or bottom? 

At top (acceleration is downward): 
Weight (m*g): downward 
Normal force (Ntop): upward 

Thus Newton's 2nd law reads: 
m*g - Ntop = m*a 

At top (acceleration is upward): 
Weight (m*g): downward 
Normal force (Nbottom): upward 

Thus Newton's 2nd law reads: 
Nbottom - m*g = m*a 

Solve for normal forces in both cases. Normal force is apparent weight, the weight that the passenger thinks is her weight when measuring by any method in the gondola reference frame: 
Ntop = m*(g - a) 
Nbottom = m*(g + a) 


Substitute a: 
Ntop = m*(g - 2*Pi^2*d/T^2) 
Nbottom = m*(g + 2*Pi^2*d/T^2) 

We are interested in the ratio of weight (gondola reference frame weight to weight when on the ground): 
Ntop/(m*g) = m*(g - 2*Pi^2*d/T^2)/(m*g) 
Nbottom/(m*g) = m*(g + 2*Pi^2*d/T^2)/(m*g) 

Simplify: 
Ntop/(m*g) = 1 - 2*Pi^2*d/(g*T^2) 
Nbottom/(m*g) = 1 + 2*Pi^2*d/(g*T^2) 

Data: 
d:=22 m; T:=12.5 sec; g:=9.8 N/kg; 

Results: 
Ntop/(m*g) = 71.64%...she feels "light" 
Nbottom/(m*g) = 128.4%...she feels "heavy"</span>
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3 years ago
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