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Feliz [49]
3 years ago
5

he Garcia family bought 400 yards of fencing to enclose a circular wildflower garden. They will use all of the fencing. a. What

is the diameter of the garden? b. Use your answer to part a to find the area enclosed by the fence?

Mathematics
1 answer:
frez [133]3 years ago
6 0

9514 1404 393

Answer:

  • 127.32 yards diameter
  • 12,732.4 square yards area

Step-by-step explanation:

The diameter can be found from the circumference using the relation ...

  C = πd

  d = C/π = (400 yd)/π ≈ 127.32 yd . . . . diameter

The area is ...

  A = πr²

where the radius (r) is half the diameter.

  A = π(63.662 yd)² ≈ 12,732.4 yd² . . . . area

_____

<em>Additional comment</em>

We have used a full-precision value for pi. If you use 3.14, your answers will be different. Your diameter will be about 127.4 yards; your area about 12,738.9 yd².

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SpyIntel [72]

is there more ???????

6 0
2 years ago
What shape is similar to the original shape
Yuri [45]

Answer c

Step-by-step explanation:

they have to be equivalent

8 0
2 years ago
Find the TWO integers whos product is -12 and whose sum is 1<br>​
Deffense [45]

Answer:

\rm Numbers = 4 \ and \ -3.

Step-by-step explanation:

Given :-

The sum of two numbers is 1 .

The product of the nos . is 12 .

And we need to find out the numbers. So let us take ,

First number be x

Second number be 1-x .

According to first condition :-

\rm\implies 1st \ number * 2nd \ number= -12\\\\\rm\implies x(1-x)=-12\\\\\rm\implies x - x^2=-12\\\\\rm\implies x^2-x-12=0\\\\\rm\implies x^2-4x+3x-12=0\\\\\rm\implies x(x-4)+3(x-4)=0\\\\\rm\implies (x-4)(x+3)=0\\\\\rm\implies\boxed{\red{\rm x = 4 , -3 }}

Hence the numbers are 4 and -3

4 0
2 years ago
Read 2 more answers
MARKIN BRAINIEST!!! GIVIN 30PTS!!!
Sedbober [7]

Answer:

  • (-16x² +10x -3) +(4x² -29x -2)
  • (2x² -11x -9) -(14x² +8x -4)
  • 2(x -1) -3(4x² +7x +1)

Step-by-step explanation:

I find it takes less work if I can eliminate obviously wrong answers. Toward that end, we can consider the constant terms only:

  1. -3 +(-2) = -5 . . . . possible equivalent
  2. -10 -5 = -15 . . . . NOT equivalent
  3. 3(-5) -2(5) = -25 . . . . NOT equivalent
  4. -9 -(-4) = -5 . . . . possible equivalent
  5. -7 -(-5) = -2 . . . . NOT equivalent
  6. 2(-1) -3(1) = -5 . . possible equivalent

Now, we can go back and check the other terms in the candidate expressions we have identified.

  1. (-16x² +10x -3) +(4x² -29x -2) = (-16+4)x² +(10-29)x -5 = -12x² -19x -5 . . . OK

  4. (2x² -11x -9) -(14x² +8x -4) = (2-14)x² +(-11-8)x -5 = -12x² -19x -5 . . . OK

  6. 2(x -1) -3(4x² +7x +1) = -12x² +(2 -3·7)x -5 = -12x² -19x -5 . . . OK

All three of the "possible equivalent" expressions we identified on the first pass are fully equivalent to the target expression. These are your answer choices.

7 0
3 years ago
Read 2 more answers
Consider the function g(x) = (x-e)^3e^-(x-e). Find all critical points and points of inflection (x, g(x)) of the function g.
Elden [556K]

Answer:

The answer is "cirtical\  points \ (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})"

Step-by-step explanation:

Given:

g(x) = (x-e)^3e^{-(x-e)}

Find critical points:

g(x) = (x-e)^3e^{(e-x)}

differentiate the value with respect of x:

\to g'(x)= (x-e)^3 \frac{d}{dx}e^{e-r} +e^{e-r}  \frac{d}{dx}(x-e)^3=(x-e)^2 e^{(e-x)} [-x+e+3]

critical points g'(x)=0

\to (x-e)^2 e^{(e-x)} [e+3-x]=0\\\\\to e^{(e-x)}\neq 0 \\\\\to (x-e)^2=0\\\\ \to [e+3-x]=0\\\\\to x=e\\\\\to x=e+3\\\\\to x= e,e+3

So,

The critical points of (x,g(x))\equiv  (e,0),(e+3,\frac{27}{e^3})

7 0
3 years ago
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