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Papessa [141]
4 years ago
7

Which system of equations is consistent and dependent?

Mathematics
1 answer:
Bad White [126]4 years ago
5 0

Answer: The answer is the third option

Step-by-step explanation:

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(cotx+cscx)/(sinx+tanx)
Butoxors [25]

Answer:   \bold{\dfrac{cot(x)}{sin(x)}}

<u>Step-by-step explanation:</u>

Convert everything to "sin" and "cos" and then cancel out the common factors.

\dfrac{cot(x)+csc(x)}{sin(x)+tan(x)}\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)}{1}+\dfrac{sin(x)}{cos(x)}\bigg)\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg[\dfrac{sin(x)}{1}\bigg(\dfrac{cos(x)}{cos(x)}\bigg)+\dfrac{sin(x)}{cos(x)}\bigg]\\\\\\\bigg(\dfrac{cos(x)}{sin(x)}+\dfrac{1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)}{cos(x)}+\dfrac{sin(x)}{cos(x)}\bigg)

\text{Simplify:}\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\div\bigg(\dfrac{sin(x)cos(x)+sin(x)}{cos(x)}\bigg)\\\\\\\text{Multiply by the reciprocal (fraction rules)}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)cos(x)+sin(x)}\bigg)\\\\\\\text{Factor out the common term on the right side denominator}:\\\\\bigg(\dfrac{cos(x)+1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)(cos(x)+1)}\bigg)

\text{Cross out the common factor of (cos(x) + 1) from the top and bottom}:\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times\bigg(\dfrac{cos(x)}{sin(x)}\bigg)\\\\\\\bigg(\dfrac{1}{sin(x)}\bigg)\times cot(x)}\qquad \rightarrow \qquad \dfrac{cot(x)}{sin(x)}

6 0
4 years ago
What is 56 as a reduced fraction?
Gala2k [10]
56 reduced as a fraction is 56/100 or 14/25
7 0
4 years ago
Read 2 more answers
|3k-2|=2|k+2| how do I do this when the 2 is on the other side??
grin007 [14]
|3k-2|=2|k+2l
Do Distributive Property and take 2 times by everything in the parenthesis. That will leave you with |3k-2|=2k+4. Then add like terms. 3k+2k=5k. Then -2+4=2. So you end up with 5k+2. I believe I'm right. If not please tell me.
3 0
3 years ago
Elliot spent 3/5 of his money on stereo equipment and 1/6 of the money he had left on lunch. He left the house with $24. How muc
riadik2000 [5.3K]
$24/5 = $4.8 x 3 = $14.4
$24/6 = $4 x 1 = $4
$14.4 + $4 = $18.4
$24 - $18.4 = $5.6
6 0
3 years ago
What are the solution(s) to the quadratic equation 50 - x2 = 0?
jekas [21]

Answer:

x = 5\sqrt{2}

Step-by-step explanation:

given, 50 - x^2 = 0

add x^2 to both sides, 50 = x^2

square root both sides, \sqrt{50}\\ = \sqrt{x^{2} }

simplify, 50 / 5 = 10 / 5 = 2

you have a pair of 5's, and a 2, 5\sqrt{2} = x

5 0
3 years ago
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