First you had to rewrite the problem with eighteen as the three times six is equal to eighteen.
Then you factor it out by the common term of six.
Final answer:
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Answer:
0.614125
Step-by-step explanation:
Given that a manufacturing process with a quality inspection station has on an average 15% of parts are defective.
As soon as one defective part is found, the process is stopped.
We find that number of defectives would be binomial because each part randomly selected has a constant probability of 0.15 being defective
Probability that at least 11 total parts will be inspected before the process is stopped/8 parts have been inspected without finding a defective part
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= Probability of 9th, 10th, 11th should not be defective
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