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4 years ago

Math I need help with it!!!!!

Mathematics

1 answer:

Snezhnost [94]4 years ago

8 0

Answer:

each ouce is worth 25 cents

solution

in order to solve this you need to create proportions so

10 ounces

per $2.50

well you want this to be a unit rate so you would have

10 ounces = 1 ounce

2.50 x

to get to the unit rate, you can see that you divided 10 from 10 ounces so you would do the same to the bottom ...

2.50/10 which is equal to 0.25.

You might be interested in

Please help me, I don’t understand how I keep getting it wrong!

GenaCL600 [577]

9514 1404 393

Answer:

1.2 t/m³

Step-by-step explanation:

1 tonne is 1 Mg = 10⁶ g

1 m³ is (100 cm)³ = 10⁶ cm³

The conversion is ...

(1.2 g/cm³) · (1 t)/(10⁶ g) · (10⁶ cm³)/(1 m³)

= 1.2(10⁶)/(10⁶) t/m³

= 1.2 t/m³

For this conversion, the numerical value does not change. Megagrams per cubic meter is the same ratio as grams per cubic centimeter.

6 0

3 years ago

Jasmine used the number line to find the distance between 0 and 5. What was Jasmine’s error? Jasmine should have counted from 5

Jobisdone [24]

Answer:

The answer is "Option C".

Step-by-step explanation:

In this question, the distance value is -5 that's why option c is correct.

5 0

3 years ago

the average lifespan of a horse is 40 years, which is five times longer than the average lifespan of a guinea pig. Use the bar d

polet [3.4K]

All you have to do is divide 40 by five and you've got your answer. I don't have the required diagram, but that would basically mean that the average lifespan of a guinea pig is about eight years, which is being generous in reality (they usually live for about 4-8 years in real life).

3 0

3 years ago

You purchased a stock at a price of $51.17. The stock paid a dividend of $1.75 per share and the stock price at the end of the y

ipn [44]

Answer: i think it is 109.51

Step-by-step explanation:

7 0

3 years ago

In a recent year, a poll asked 2362 random adult citizens of a large country how they rated economic conditions. In the poll,

Harman [31]

Answer:

a) The 99% confidence interval is given by (0.198;0.242).

b) Based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

c) $\alpha=0.01$

Step-by-step explanation:

Data given and notation

n=2362 represent the random sample taken

X represent the people who says that they would watch one of the television shows.

$\hat p=\frac{X}{n}=0.22$ estimated proportion of people rated as Excellent/Good economic conditions.

$p_o=0.24$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 24% of people are rated with good economic conditions:

Null hypothesis: $p=0.24$

Alternative hypothesis: $p \neq 0.24$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Part a: Test the hypothesis

Check for the assumptions that he sample must satisfy in order to apply the test

a)The random sample needs to be representative: On this case the problem no mention about it but we can assume it.

b) The sample needs to be large enough

np = 2362x0.22=519.64>10 and n(1-p)=2364*(1-0.22)=1843.92>10

Condition satisfied.

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.22 -0.24}{\sqrt{\frac{0.24(1-0.24)}{2362}}}=-2.28$

The confidence interval would be given by:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

The critical value using $\alpha=0.01$ and $\alpha/2 =0.005$ would be $z_{\alpha/2}=2.58$ . Replacing the values given we have:

$0.22 - (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.198$

$0.22 + (2.58)\sqrt{\frac{0.22(1-0.22)}{2362}}=0.242$

So the 99% confidence interval is given by (0.198;0.242).

Part b

Statistical decision 

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided is $\alpha=0.01$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z$

So based on the p value obtained and using the significance level assumed $\alpha=0.01$ we have $p_v>\alpha$ so we can conclude that we fail to reject the null hypothesis, and we can said that at 1% of significance the proportion of people who are rated with Excellent/Good economy conditions not differs from 0.24. The interval also confirms the conclusion since 0.24 it's inside of the interval calculated.

Part c

The confidence level assumed was 99%, so then the signficance is given by $\alpha=1-confidence=1-0.99=0.01$

6 0

3 years ago