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Paraphin [41]
4 years ago
13

Find 12 +13 - (-9)+(-19.4) +3.3

Mathematics
2 answers:
Rina8888 [55]4 years ago
5 0

Answer:

17.9

Step-by-step explanation:

You could use PEMDAS but you don't really need to because this is just adding an subtracting.

Ket [755]4 years ago
3 0

Answer: 17.9

Step-by-step explanation:

25−(−9)−19.4+3.3

=34−19.4+3.3

=14.6+3.3

=17.9

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Step-by-step explanation:

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1. There are 64 pretzels in a 16-ounce bag of chocolate-covered pretzels.
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A civil engineer is analyzing the compressive strength of concrete. Compressive strength is approximately normally distributed w
nignag [31]

Answer:

a) 3250-1.96\frac{31.623}{\sqrt{18}}=3232.108    

3250+1.96\frac{31.623}{\sqrt{18}}=3267.892    

So on this case the 95% confidence interval would be given by (3232.108;3267.892)    

b) For this case since the value of 3270 is higher than the upper limit for the confidence interval so we can conclude that the true mean is not higher than 3270 at 5% of signficance. We can reject the claim at the significance level of 5%.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X= 3250 represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma^2 =1000represent the sample standard variance

s = \sqrt{1000} represent the sample deviation

n=12 represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96

Now we have everything in order to replace into formula (1):

3250-1.96\frac{31.623}{\sqrt{18}}=3232.108    

3250+1.96\frac{31.623}{\sqrt{18}}=3267.892    

So on this case the 95% confidence interval would be given by (3232.108;3267.892)    

Part b

For this case since the value of 3270 is higher than the upper limit for the confidence interval so we can conclude that the true mean is not higher than 3270 at 5% of signficance. We can reject the claim at the significance level of 5%.

8 0
3 years ago
Help me solve this question
OLEGan [10]

Consider the first term on the left side.

\displaystyle \frac{2\sin{A}}{\cos{3A}}\\\\=\frac{2\sin{A}\cos{A}}{\cos{3A}\cos{A}}\qquad\text{multiply by cos(A)/cos(A)}\\\\=\frac{\sin{2A}}{\cos{3A}\cos{A}}\qquad\text{double angle formula for sin}\\\\=\frac{\sin{(2A-A)}}{\cos{3A}\cos{A}}=\frac{\sin{3A}\cos{A}-\cos{3A}\sin{A}}{\cos{3A}\cos{A}}\\\\=\tan{3A}-\tan{A}

Then the sum of the three terms on the left is

\left(\tan{3A}-\tan{A}\right)+\left(\tan{9A}-\tan{3A}\right)+\left(\tan{27A}-\tan{9A}\right)\\\\=\tan{27A}-\tan{A}\qquad\text{Q.E.D.}

4 0
4 years ago
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