All categories

2 years ago

Identify the volume of a cone with radius 6 m and height 11 m. HELP PLEASE!!

Mathematics

1 answer:

Lera25 [3.4K]2 years ago

6 0

Answer: 414.48

Step-by-step explanation:

r: the radius of the base

h: height

The volume of a cone is given by:

V = π ∙ r2 ∙ h / 3,

where π ∙ r2 is the base area of the cone.

π defines the ratio of any circle's circumference to its diameter and is approximately equal to 3.141593, however the value 3.14 is often used.

You might be interested in

The school band sold 3,305 raffle tickets to raise money for a trip to Disney World. Which equation shows the relationship betwe

Iteru [2.4K]

I believe it would be D.

4 0

2 years ago

Read 2 more answers

If 11 - 3x = x, then 20x=

dimaraw [331]

Answer:

20x = 55

Step-by-step explanation:

First you have to add 3x to both sides of 11-3x=x

$11-3x=x\\+3x=+3x\\11=4x$

Now that you have 11 = 4x you divide 4 on both sides $\frac{11}{4} =\frac{4x}{4}$

11/4 = x

But you can't divide 11 by 4 unless you are looking for the decimal form of 11/4 which is 2.75

so now we take 11/4 or 2.75 depending on if you need your answer in fraction or as a decimal and replace that with x however both will equal the number 55

$20(\frac{11}{4})=55\\20(2.75)=55$

4 0

2 years ago

Sin^2(x/2)=sin^2x <br> Find the value of x

Veronika [31]

$\sin^2\dfrac x2=\sin^2x$
$\dfrac{1-\cos x}2=1-\cos^2x$
$1-\cos x=2-2\cos^2x$
$2\cos^2x-\cos x-1=0$
$(2\cos x+1)(\cos x-1)=0$
$\implies\begin{cases}2\cos x+1=0\\\cos x-1=0\end{cases}$ $\implies\begin{cases}\cos x=-\frac12\\\cos x=1\end{cases}$

The first case occurs in $0\le x$ for $x=\dfrac{2\pi}3$ and $x=\dfrac{4\pi}3$ . Extending the domain to account for all real $x$ , we have this happening for $x=\dfrac{2\pi}3+2n\pi$ and $\dfrac{4\pi}3+2n\pi$ , where $n\in\mathbb Z$ .

The second case occurs in $0\le x$ when $x=0$ , and extending to all reals we have $x=2n\pi$ for $n\in\mathbb Z$ , i.e. any even multiple of $\pi$ .