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il63 [147K]
3 years ago
14

In a basketball skills competition, Corson successfully made 5 of 7 shots and Charleigh made 3 of 5

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
6 0

Answer:

Corson had a better performance at the skills competition.

Step-by-step explanation:

In order to determine which player had a better performance at the skills competition, we need to find the percentage performance of both the players.

Therefore,

Corson's percentage performance

=\frac{5}{7}\times 100= 71.43%

Charleigh's percentage performance

=\frac{3}{5}\times 100= 60%

\because Corson's percentage performance > Charleigh's percentage performance

So, Corson had a better performance at the skills competition.

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Answer: 0.16

Step-by-step explanation:

Given that the run times provided are normally distributed ;

Mean(x) of distribution = 3 hours 50 minutes

Standard deviation(s) = 30 minutes

The probability that a randomly selected runner has a time less than or equal to 3 hours 20 minutes

3 hours 20 minutes = (3 hrs 50 mins - 30 mins):

This is equivalent to :

[mean(x) - 1 standard deviation]

z 1 standard deviation within the mean = 0.84

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1 - 0.8413 = 0.1587

= 0.16

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3 years ago
4. Find the range of the data set: 3, 21, 17, 17, 34, 22, 26<br><br>Please help​
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Answer:

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Step-by-step explanation:

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3 years ago
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3 years ago
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alukav5142 [94]

Answer:

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Step-by-step explanation:

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