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Ugo [173]
3 years ago
5

Identify the x-intercept of the linear equation 3x+y-9=0

Mathematics
1 answer:
timama [110]3 years ago
4 0

Answer:

9

Step-by-step explanation:

Get the equation into the form y = mx + c

3x + y - 9 = 0

y = -3x + 9

The y intercept is 9

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<em>ap</em><em>p</em><em>ly </em><em>angle</em><em> </em><em>sum </em><em>property</em><em> </em><em>of </em><em>triangle</em><em> </em><em>in </em><em>the </em><em>given</em><em> </em><em>traingle </em><em>(</em><em> </em><em>instead</em><em> </em><em>of </em><em>this </em><em>u </em><em>can </em><em>write</em><em> </em><em>sum </em><em>of </em><em>all </em><em>the </em><em>interior</em><em> </em><em>angles </em><em>of </em><em>triangle</em><em> </em><em>is </em><em>1</em><em>8</em><em>0</em><em>°</em><em>)</em>

<em>so,</em>

<em>→</em><em> </em><em>8</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>5</em><em>0</em><em>°</em><em> </em><em>+</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em>

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<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>1</em><em>8</em><em>0</em><em>°</em><em> </em><em>-</em><em> </em><em>1</em><em>3</em><em>0</em><em>°</em>

<em>→</em><em> </em><em>x </em><em>=</em><em> </em><em>5</em><em>0</em><em>°</em>

<em>therefore</em><em>,</em><em> </em><em>value</em><em> </em><em>of </em><em>x </em><em>is </em><em>5</em><em>0</em><em>°</em><em>.</em>

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7 0
2 years ago
Read 2 more answers
Point R is located at (-9,8) and point T is located at (-9,-7) on a coordinate plane.
poizon [28]

Answer:

15 unit

Step-by-step explanation:

Applying

/RT/ = √[(y₂-y₁)²+(x₂-x₁)²]............. Equation 1

Where /RT/ = distance between point R and Point T

From the question,

Given: y₁ = -9, x₁ = 8, y₂ = -9, x₂ = -7

Substitute these values into equation 1

/RT/ = √[(-9-(-9))²+(-7-8)²]

/RT/ = √[(0)²+(-15)²]

/RT/ = √225

/RT/ = 15 unit

Hence the distance between point R and point T is 15 unit

3 0
3 years ago
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