Answer:
slope = -1.5
Step-by-step explanation:
A set of three or more points are said to be collinear if they all lie on the same straight line.
We have been given the following collinear set of points;
P(0, 3), Q(2, 0), R(4, -3)
This implies that P, Q, and R lie on the same line.
The slope of a line is defined as; (change in y)/(change in x)
Using the points P and Q, the slope of the line is calculated as;
(0-3)/(2-0) = -3/2 = -1.5
Answer:
(x+1)^2 + (y-3)^2 = 16
Step-by-step explanation:
The equation of a circle is given by
(x-h)^2 + (y-k)^2 = r^2
Where (h,k) is the center and r is the radius
(x--1)^2 + (y-3)^2 = 4^2
(x+1)^2 + (y-3)^2 = 4^2
(x+1)^2 + (y-3)^2 = 16
Answer:
149.54
Step-by-step explanation:
No idea how I got this, but it is correct. I just plugged it into Omni calculator and it gave me that. :p
Let 1993 = time 0 = 0.
Let 1999 = time 6 = 6
Let 2012 = time 19 = 19
So, a = 171 (million). First solve for k.
176 = 171 e^k6
176/171 = e^(k*6)
ln (176/171) = 6k
k = 1/6 ln (176/171)
So, in 2012 we have: P(19) = 171 e^(19k), where k = 1/6 ln (176/171)
Hope this helped!
Answer:
84,6km/h
Step-by-step explanation:
the whole journey was
in the first part the car travels 50km, in the second part 120km and in the third part we can find it with a simple rule of three
90km--->60 min
X<--------35min= 52.5 km the car made in the last part
50km+120km+52,5km=222.5km was all the journey
and he made it in:
- the last part in 35min,
- in the second part we know that the car was going at 80km/h and that he made 120km so:
80km--->60 min
120km--->90 min
- in the first part we know that the car was going at 25m/s and he made 50km. 25m/s*1km/1000m*3600s/1h= we obtain the speed in km/h=90km/h
90km---->60min
50km---->x=33,333 min
The whole journey last 33,333min+90min+35min=158.333min
if we express that in hour = 158.333min*1hr/60min=2.63
the car made 222.5km in 2.63 hour
so the average speed was
222.5---->2.63hr
X--------1hr=84,6
the average speed was 84,6km/h
