Helpppp What is the sum of the first twelve numbers of the sequence 3, 7, 11, 15,...?
1 answer:
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Let's assume
people were in the original group of winners as x
A group of winning ticket holders share equally 90,000,000 lottery
Before the money is divided, three more winning ticket holders are declared
so, total number of winning tickes =x+3
each persons share is reduced to 5,000,000
so, total money =5,000,000*(x+3)
and this must be equal to total money
now, we can solve for x
and we get
Subtrac both sides by 3
so,
number of people were in the original group of winners is 15 ...........Answer