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3 years ago

Multiply the binomials: (a-2) • (a-8)

Mathematics

2 answers:

umka21 [38]3 years ago

6 0

Answer:

a^2 -10a +16

Step-by-step explanation:

(a-2) • (a-8)

FOIL

first a*a = a^2

outer: a * -8 = -8a

inner: -2 *a = -2a

last: -2 *-8 = 16

Add them together

a^2 -8a -2a+16

Combine like terms

a^2 -10a +16

vfiekz [6]3 years ago

3 0

Answer:

Step-by-step explanation:

(a-2) (a-8) , distribute a over (a-8) then -2 over (a-8)

a²-8a-2a+16, combine like terms

a² -10a +16

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Solve the equation: 3.2/(z-1/2) = 2.667/(z+1/3)

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Answer:

Z = 2489/533

Step-by-step explanation:

I went on photo math and solved it

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3 years ago

Renee wants to join the local gym. The cost of the membership can be represented by the equation, y=12x+35, where x is the numbe

Montano1993 [528]

The initial membership fee before any months are considered is 35.

Substitute 0 with x because no months have been considered. Like what was previously said, y is the total cost, so:

Y=12(0)+35
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3 years ago

A contractor developed a multiplicative time-series model to forecast the number of contracts in future quarters, using quarterl

dusya [7]

There is a missing content in the question.

After the statements and before the the options given; there is an omitted content which says:

Referring to Table 16-5, in testing the coefficient of X in the regression equation (0.117) the results were a t-statistic of 9.08 and an associated p-value of 0.0000. Which of the following is the best interpretation of this result?

Answer:

C. The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05).

Step-by-step explanation:

From the given question:

The resulting regression equation can be represented as:

$\hat Y = 3.37 + 0.117 X - 0.083 Q_1 + 1.28 Q_2 + 0.617Q_3$

where;

the estimated number of contracts in a quarter X is the coded quarterly value with X = 0

the first quarter of 2010 Q1 is a dummy variable equal to 1 in the first quarter of a year and 0 otherwise

Q2 is a dummy variable equal to 1 in the second quarter of a year and 0 otherwise

Q3 is a dummy variable equal to 1 in the third quarter of a year and 0 otherwise

Our null and alternative hypothesis can be stated as;

Null hypothesis :

$H_0 :$ The quarterly growth rate in the number of contracts is not significantly different from 0% (? = 0.05)

$H_a:$ The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

The decision rule is to reject the null hypothesis if the p-value is less than 0.05.

From the missing omitted part we added above; we can see that the t-statistics value = 9.08 and the p-value = 0.000 .

Conclusion:

Thus; we reject the null hypothesis and accept the alternative hypothesis. i.e

The quarterly growth rate in the number of contracts is significantly different from 0% (? = 0.05)

4 0

3 years ago

A figure in the first quadrant is rotated 180° counterclockwise about the origin. In which quadrant will the rotated figure appe

amm1812

I believe quadrant 3

4 0

3 years ago

Read 2 more answers

I need help Please help ASAP

soldi70 [24.7K]

Answer:

The volume of the solid is $1,021m^3$

Step-by-step explanation:

1. Cylinder

For find the volume of a cylinder we use the next formula:

$V_{cylinder} = \pi h r^2 = \pi \cdot 9m\cdot (5m)^2 \approx 706.86m^3$

Then the volume of the cylinder is equal to $706.86m^3$

2. Cones

For find the volume of a cone we use the next formula:

$V_{cone} = \pi \frac{h}{3} r^2 = \pi \cdot \frac{6m}{3} \cdot (5m)^2 \approx 157.08m^3$

However there are two cones so we have to multiply the volume of one cone for two and we get the total volume for the cones which is $314.16m^3$

3. Sum of the volumes

Finally we sum the volumes of the cylinder and the cones for get the final result

$V_{cylinder} + V_{cones} = 706.86m^3 + 314.16m^3 \approx 1021m^3$

So approximating the result is $1021m^3$

5 0

2 years ago