Answer: {(5,0), (3,4)}
Step-by-step explanation:
You can apply the Substitution method:
- Solve for y from the second equation.
- Substitute into the first equation and solve for x.
Then:


(Remember that:
)

Substitute the values obtained into one of the original equation and solve for y:

The solution set is: {(5,0), (3,4)}
Answer: See step by step
Step-by-step explanation: Angle 2 and 3 are vertical angles since they both share a vertex and has cross intersecting lines. Angle 6 and 7 are supplementary angles because they forma linear pair.
the answer is a add -19w and dont forget to do it on each side
Hold on, does the equation look like this? (x^2+6)/x-6? Because if so then you'd substitute nine for x first. Then you'd multiply nine by itself getting eighty-one, after that add six to get eighty-seven. substitute nine for x one more and subtract six. take eighty-seven divided by three to get an answer of twenty-nine. But if the equation is saying the square of nine aside from nine squared then you'd have an entirely different problem. That one would look similar to *square symbol*(9)+6/9-6
, You'd solve this by finding the square of nine which is three then you'd add six and get a numerator of nine. Then you go about the bottom the same as you would have in the first equation, subtract six from nine giving you a denominator of three so you now have nine over three which simplified is three.
The two answers are 29 or 3 depending on the equation.
Answer:
Expected value for 4 tickets = $ -7.6
Step-by-step explanation:
Given - A lottery offers one $900 prize, one $600 Prize, three $400 prizes, and four $100 prizes. One thousand tickets are sold at $5 each.
To find - Find the expectation if a person buys four tickets. Assume that the player's ticket is replaced after each draw and that the same ticket can win more than one prize. Round to two decimal places for currency problems.
Proof -
Given that,
A lottery offers
one $ 900 prize
one $ 600 prize
three $ 400 prizes
Four $ 100 prizes
And
One thousand tickets are sold at $ 5 each
Now,
If the person bought 1000 tickets then the prize he gets is
= 900 + 600 + 3×400 + 4×100
= 900 + 600 + 1200 + 400
= $3100
And
The cost of 1000 tickets = 5×1000 = $ 5000
Now,
Price 1 ticket =
= $ 3.1
⇒Expectation of 1 ticket = $ 3.1 - 5 = $ -1.9 (Here $5 is price of 1 ticket)
⇒Expected value for 4 tickets = $ 4× -1.9 = $ -7.6
⇒Expected value for 4 tickets = $ -7.6