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2 years ago

How do you solve 6<_2g?

Mathematics

1 answer:

horrorfan [7]2 years ago

3 0

Divide both sides by 2 to isolate variable g.

You're left with 6 / 2 < g which equals 3 < g.

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Pleaseeeeee help me pleasee

Nikitich [7]

Lol I just needed help with this kinda stuff...

I’m not very caught up with this stuff I feel your pain I’m very sorry if I’m wrong =/

10?

6 0

2 years ago

Sari drives 55 miles per hour. Which equation shows the proportional relationship between hours (h) and miles (m)?

Finger [1]

Answer:

$m=55h$

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form $k=\frac{y}{x}$ or $y=kx$

In a proportional relationship the constant of proportionality k is equal to the slope m of the line and the line passes through the origin

Let

m ----> the distance in miles (y-coordinate)

h ----> the time in hours (x-coordinate)

In this problem the constant of proportionality k is given and is equal to

$k=55\ \frac{miles}{hour}$ ----> the speed

substitute

$m=55h$

8 0

3 years ago

Using the information in the customer order, determine the length and width of the garden. Enter the dimensions. ↓

SashulF [63]

Answer:

Length: 14 feet Width: 1 foot

Step-by-step explanation:

This is the only way to have a rectangle that has a perimeter of 30 feet, and an area of 14 feet.

For perimeter:

14 + 14 = 28

1 + 1 = 2

2 + 28 = 30

These dimensions have a perimeter of 30.

For area:

14 x 1 = 14

These dimesnions also have an area of 14.

So, 14 and 1 are the correct dimensions!

6 0

2 years ago

Write each fraction as a decimal. Then identify each decimal as terminating or repeating.

cluponka [151]

1/6 = 0.16
1/8 = 0.125
1/11 = 0.09
2/9 = 0.22
4/5 = 0.8
5/9 = 0.56
1/2 = 0.5
7/9 = 0.78

5 0

2 years ago

If the line t is a transversal of lines I and m, NAME THE SPECIAL ANGLE PAIR RELATIONSHIP of the given angle pairs.

Hunter-Best [27]

Answer:

a. <1 and <3

Step-by-step explanation:

8 0

2 years ago