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2 years ago

Find the slope of the line perpendicular to the line passing through the given points: (-4, 8) and (-2, 5)

Mathematics

1 answer:

frozen [14]2 years ago

4 0

Answer:

$\frac{3}{2}$

Step-by-step explanation

The slope of a perpendicular line would be (-x) if the slope of the original line was (x).

The formula for finding slope is:

$\frac{y_2-y_1}{x_2-x_1}$

Inserting your problem would make the equation look like:

$\frac{5-8}{-2+4}$

Simplify:

$\frac{-3}{2}$

That is the slope of the given line, to find the slope of the line perpendicular to that one, we would put into (-x)

Answer:

$\frac{3}{2}$

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Bad White [126]

Answer:

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Step-by-step explanation:

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3 years ago

Alejandro made an error in the steps below when determining the equation of the line that is perpendicular to line 4x - 3y = 8 a

Ronch [10]

Hello:
the equation is : y = ax+b
the slope is a : a×(4/3) = -1......( perpendicular to a line with a slope of 4/3) because : 4x-3y =8...y=(4/3)x-8/3 )

a = -3/4 y=(-3/4)x+b
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2 years ago

Write an equation of a line in point-slope, slope-intercept, and standard form that has

Inga [223]

Answer:

(a) $y + 4x - 14 = 0$

(b) $y = -4x + 14$

Step-by-step explanation:

The formula for calculating the equation of line in point - slope form is given as :

$y-y_{1} = m(x-x_{1} )$

where m is the slope

Given from the question :

m = - 4

$x_{1}$ = 2

$y_{1}$ = 6

Substituting into the formula , we have :

$y - 6 = - 4(x - 2)$

$y - 6 = -4x + 8$

$y + 4x - 6 - 8 = 0$

$y + 4x - 14 = 0$

Therefore :

(a) the equation of the line in point - slope form is $y + 4x - 14 = 0$

(b) to write it in slope - intercept form , we will make y the subject of the formula , which will give : $y = -4x + 14$

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Step-by-step explanation:

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2 years ago

Find the slope of the line perpendicular to the line passing through the given points: (-4, 8) and (-2, 5)​

Find the slope of the line perpendicular to the line passing through the given points: (-4, 8) and (-2, 5)