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3 years ago

Find the slope of the line perpendicular to the line passing through the given points: (-4, 8) and (-2, 5)

Mathematics

1 answer:

frozen [14]3 years ago

4 0

Answer:

$\frac{3}{2}$

Step-by-step explanation

The slope of a perpendicular line would be (-x) if the slope of the original line was (x).

The formula for finding slope is:

$\frac{y_2-y_1}{x_2-x_1}$

Inserting your problem would make the equation look like:

$\frac{5-8}{-2+4}$

Simplify:

$\frac{-3}{2}$

That is the slope of the given line, to find the slope of the line perpendicular to that one, we would put into (-x)

Answer:

$\frac{3}{2}$

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Amirah's family is driving to her uncle's house. The family travels 383.5 miles between 10:15 am and 4:45 pm. Calculate the fami

ddd [48]

Answer:

The family's average rate of travel for the day was 59.0 MPH.

Step-by-step explanation:

From 10:15AM to 4:45PM, they travelled a distance of 383.5 miles and a total of 6 hours and 30 minutes.

There are 60 minutes in an hour. 30 minutes translates into 1/2 an hour or .5

So, 6.5 hours and a total distance of 383.5 miles.

Velocity (MPH) = Distance (in miles) / Time (in hours)

MPH means Miles Per Hour

Variables:

Velocity (MPH) = x

Distance (in miles) = 383.5

Time (in hours) = 6.5

Plug in the variables into the formula

x = 383.5 / 6.5

Divide

x = 59.0 MPH

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3 years ago

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The Thompson Family decides to plant a total of 180 plants in order to prepare for a larger

Licemer1 [7]

Answer: 54 berry plants

Step-by-step explanation:

From the sample there are:

Lettuce = 12

Tomatoes = 6

Peppers = 3

Berries = 9

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= 9/30

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3 years ago

Monday the price of an online movie dropped $3 in the morning and then another $3 that afternoon.the following Monday morning th

Burka [1]

dropped $3 means "-3", increased $6 means "+6"

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3 years ago

In Which Quadrant is this true

34kurt

Given:

$\sin \theta$

$\tan \theta$

To find:

The quadrant in which $\theta$ lie.

Solution:

Quadrant concept:

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II, only $\sin\theta$ and $\csc\theta$ are positive.

In Quadrant III, only $\tan\theta$ and $\cot\theta$ are positive.

In Quadrant IV, only $\cos\theta$ and $\sec\theta$ are positive.

We have,

$\sin \theta$

$\tan \theta$

Here, $\sin\theta$ is negative and $\tan\theta$ is also negative. It is possible, if $\theta$ lies in the Quadrant IV.

Therefore, the correct option is D.

5 0

3 years ago

Find the slope of the line perpendicular to the line passing through the given points: (-4, 8) and (-2, 5)​

Find the slope of the line perpendicular to the line passing through the given points: (-4, 8) and (-2, 5)