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schepotkina [342]

3 years ago

14

question; The chart below shows the number of tickets to the annual teachers vs. students basketball game. How many tickets did

most of the students sell?

1 answer:

Marianna [84]3 years ago

5 0

31-40. C. 12 students sold that many, therefore it's the most.

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Solve for y -2(x + 3 y) =18

LUCKY_DIMON [66]

Answer:

y= -3y - 1/3x

Step-by-step explanation:

-2(x + 3y) = 18 Distribute the -2 to the x + 3y

-2x - 6y = 18

+2x +2x Add the 2x to both sides

-6y = 18 + 2x Divide both sides by -6

y= -3y - 1/3x

3 0

3 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0

3 years ago

Read 2 more answers

Which relation is a function?

zimovet [89]

Answer:

D

Step-by-step explanation:

A relation is a set of related points. A function is a set of related points where no inputs repeat.

A. {(1, 2), (2, 3), (3, 2), (2, 1)}

This repeats (2,3) and (2,1). Not a function.

B. {(4, 2), (3, 3), (2, 4), (3, 2)}

This repeats (3,3) and (3,2). Not a function.

C. {(1, −1), (−2, 2), (−1, 2), (1, −2)}

This repeats (1,-1) and (1,-2). Not a function.

D. {(1, 4), (2, 3), (3, 2), (4, 1)}

This doe NOT repeat. Function.

6 0

3 years ago

If you can buy 1⁄3 of a box of chocolates for 6 dollars, how much can you purchase for 4 dollars?

alukav5142 [94]

Answer:

2/9 boxes.

Step-by-step explanation:

6 / 1 / 3 = 4 / b

Cross multiply the two

6b = 4/3

Multiply 1/6 on each side

B = 4 /18

It can be reduced to 2/9.

Feel free to let me know if you need more help! :)

5 0

3 years ago

goldfiish [28.3K]

When a shape is rotated, it must be rotated around a point.

<em>To determine the location of the new triangle, Sonja must subtract (5,-1) from the coordinates of the original triangle, before rotating by </em> $90^o$ <em>.</em>

<em />

From the question, we have:

$C = (5,-1)$ --- the center of rotation

Let the vertices of the triangle be (x,y).

First, she must subtract the coordinates of the center of rotation from the vertices of the triangle.

This gives:

$(x,y) \to (x - 5, y + 1)$

Then the vertices are rotated by $90^o$

<u />

<u>The rule of </u> $90^o$ <u> rotation is:</u>

$(x,y) \to (-y,x)$

So, we have:

$(x - 5,y + 1) \to (-y - 1,x - 5)$

From the attachment, the coordinates of the triangle are: (0,2), (0,5) and (4,2)

After rotation, the coordinates are calculated as follows:

$(0,2) \to (-2-1,0-5) \to (-3,-5)$

$(0,5) \to (-5-1,0-5) \to (-6,-5)$

$(4,2) \to (-2-1,4-5) \to (-3,-1)$

Hence, the coordinates are: (-3,-5), (-6,-5) and (-3,-1)

Read more about rotations at:

brainly.com/question/1571997

3 0

3 years ago